If 5 tan β = 4, the 5 sin⁡β - 2 cos⁡β/5 sin⁡β - 2 cos⁡β  =

(a) 1/3   (b) 2/5   (c) 3/5   (d) 6

 

This question is Similar to Question 15 - NCERT Exemplar - MCQ

[MCQ] If 5 tanβ = 4, then 5 𝑠𝑖𝑛𝛽 − 2 cos𝛽 / 5 sin𝛽 + 2 cos𝛽 = - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard

part 2 - Question 18 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

 

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Question 18 If 5 tan β = 4, the (5 sin⁡〖𝛽 〗− 2 cos⁡𝛽)/(5 sin⁡〖𝛽 〗+ 2 cos⁡𝛽 ) = (a) 1/3 (b) 2/5 (c) 3/5 (d) 6 Given 5 tan 𝛽 = 4 tan 𝛽 = 𝟒/𝟓 Now, (5 sin⁡〖𝛽 〗− 2 cos⁡𝛽)/(5 sin⁡〖𝛽 〗+ 2 cos⁡𝛽 ) Dividing numerator and denominator by cos 𝛽 = (5 sin⁡𝛽/cos⁡𝛽 − 2 co𝑠⁡𝛽/cos⁡𝛽 )/(5 sin⁡𝛽/cos⁡𝛽 + 2 co𝑠⁡𝛽/cos⁡𝛽 ) = (𝟓 𝐭𝐚𝐧⁡〖𝛽 − 𝟐〗)/(𝟓 𝐭𝐚𝐧⁡〖𝛽 + 𝟐〗 ) Putting tan θ = 𝟒/𝟓 = (5 × 4/5 − 2)/(5 × 4/5 + 2) = (4 − 2)/(4 + 2) = 2/6 = 𝟏/𝟑 So, the correct answer is (a)

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