If the system of equations 3x + y = 1 and (2k – 1)x + (k – 1)y = 2k + 1

 is inconsistent, then k =

(a) -1   (b) 0  (c) 1  (d) 2

 

[MCQ] If the system of equations 3x + y = 1 and (2k-1)x +(k-1)y = 2k+1 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard

part 2 - Question 4 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 4 - CBSE Class 10 Sample Paper for 2023 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Given equations 3x + y = 1 (2k – 1)x + (k – 1)y = 2k + 1 Now, Since equations are inconsistent It means that the lines are parallel 𝑎1/𝑎2 = 𝑏1/𝑏2 ≠ 𝑐1/𝑐2 𝟑/((𝟐𝒌 − 𝟏)) = 𝟏/((𝒌 − 𝟏)) ≠ 𝟏/((𝟐𝒌 + 𝟏)) Thus, 𝟑/((𝟐𝒌 − 𝟏)) = 𝟏/((𝒌 − 𝟏)) 3(k − 1) = (2k − 1) 3k − 3 = 2k − 1 3k − 2k = −1 + 3 k = 2 So, the correct answer is (d)

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