What is the distance travelled by the plane in 30 seconds?

 

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Question 38 (ii) – Choice 1 What is the distance travelled by the plane in 30 seconds? Distance travelled by airplane in 30 seconds is BC Let BC = x Here, ∠ ABE = 90° & ∠ ACD = 90° In right angle triangle ABE tan A = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴) tan A = (" " 𝐵𝐸)/𝐴𝐵 tan 60° = 𝐵𝐸/𝐴𝐵 √3 = (" " 3000√3)/𝐴𝐵 AB = 3000 m In right angle triangle ACD tan A = (𝑆𝑖𝑑𝑒 𝑜𝑝𝑝𝑜𝑠𝑖𝑡𝑒 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴)/(𝑆𝑖𝑑𝑒 𝑎𝑑𝑗𝑎𝑐𝑒𝑛𝑡 𝑡𝑜 𝑎𝑛𝑔𝑙𝑒" " 𝐴) tan A = 𝐶𝐷/𝐴𝐶 tan 30° = 𝐶𝐷/𝐴𝐶 1/√3 = (3000√3)/𝐴𝐶 AC = 3000√𝟑 × √𝟑 = 9000 m Now, AC = AB + BC 9000 = 3000 + BC 9000 – 3000 = BC BC = 9000 – 3000 BC = 6000 m Hence, Distance travelled by airplane in 30 seconds = 6000 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.