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Ex 8.4, 3 - Evaluate (i) sin2 63 + sin2 27 / cos2 17 + cos2 73

 

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Ex 8.3, 3 Evaluate : ( sin2 63 + sin2 27 )/(cos2 17 + cos2 73 ) ( sin2 63 + sin2 27 )/(cos2 17 + cos2 73 ) = (sin2 (90 27) + sin2 27 )/(cos2 (90 73) + cos2 73 ) = (cos^2 (27 ) + sin2 27 )/(sin^2 (73 ) + cos^2 73 ) = 1/1 = 1 Hence, ( sin2 65 + sin2 27 )/(sin2 17 + sin2 73 ) = 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.