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Ex 8.3, 4 Prove the following identities, where the angles involved are acute angles for which the expressions are defined. ("1 + sec" A)/"sec A" ="sin2 A" /"1 – cos A" "[Hint : Simplify LHS and RHS separately]" (1 + sec⁡𝐴)/sec⁡〖 𝐴〗 = 1/sec⁡〖 𝐴〗 +sec⁡〖 𝐴〗/sec⁡〖 𝐴〗 = 1/sec⁡〖 𝐴〗 +1 = cos A + 1 (𝒔𝒊𝒏𝟐 𝑨)/(1 − cos⁡𝐴 ) = (𝟏 − 𝒄𝒐𝒔𝟐 𝑨)/(1 − cos⁡𝐴 ) = (12 − 𝑐𝑜𝑠2 𝐴)/(1 − cos⁡𝐴 ) = ((1 − 𝑐𝑜𝑠 𝐴)(1+ cos⁡〖𝐴)〗)/(1 − cos⁡𝐴 ) = 1 + cos A ∴ L.H.S = R.H.S Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.