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Ex 8.3, 3 Choose the correct option. Justify your choice. (iii) (sec A + tan A) (1 – sin A) sec A (B) sin A (C) cosec A (D) cos A (sec A + tan A) (1 – sin A) = (𝟏/(𝒄𝒐𝒔 𝑨)+π’”π’Šπ’β‘π‘¨/𝒄𝒐𝒔⁑〖 𝑨〗 ) (1 βˆ’sin⁑〖 𝐴)γ€— = ((1 + sin⁑〖 𝐴)γ€—)/cos⁑〖 𝐴〗 Γ—(1 βˆ’sin⁑〖 𝐴)γ€— = ((1 + sin⁑〖 𝐴)(1 βˆ’γ€– sin〗⁑〖 𝐴)γ€— γ€—)/cos⁑〖 𝐴〗 = ((1^2 βˆ’γ€– sin2〗⁑〖 𝐴)γ€—)/cos⁑〖 𝐴〗 = ((𝟏 βˆ’γ€– π¬π’π§πŸγ€—β‘γ€– 𝑨)γ€—)/cos⁑〖 𝐴〗 = (π’„π’π’”πŸ 𝑨)/cos⁑〖 𝐴〗 = cos A So, the correct answer is (d)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo