Ex 8.3, 4 (iii) - (sec A + tan A) (1 – sin A) - Trigonometry Class 10 - Ex 8.3

part 2 - Ex 8.3, 3 (iii) [MCQ] - Ex 8.3 - Serial order wise - Chapter 8 Class 10 Introduction to Trignometry

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Ex 8.3, 3 Choose the correct option. Justify your choice. (iii) (sec A + tan A) (1 – sin A) sec A (B) sin A (C) cosec A (D) cos A (sec A + tan A) (1 – sin A) = (𝟏/(𝒄𝒐𝒔 𝑨)+π’”π’Šπ’β‘π‘¨/𝒄𝒐𝒔⁑〖 𝑨〗 ) (1 βˆ’sin⁑〖 𝐴)γ€— = ((1 + sin⁑〖 𝐴)γ€—)/cos⁑〖 𝐴〗 Γ—(1 βˆ’sin⁑〖 𝐴)γ€— = ((1 + sin⁑〖 𝐴)(1 βˆ’γ€– sin〗⁑〖 𝐴)γ€— γ€—)/cos⁑〖 𝐴〗 = ((1^2 βˆ’γ€– sin2〗⁑〖 𝐴)γ€—)/cos⁑〖 𝐴〗 = ((𝟏 βˆ’γ€– π¬π’π§πŸγ€—β‘γ€– 𝑨)γ€—)/cos⁑〖 𝐴〗 = (π’„π’π’”πŸ 𝑨)/cos⁑〖 𝐴〗 = cos A So, the correct answer is (d)

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