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Ex 6.4
Ex 6.4, 2 Deleted for CBSE Board 2023 Exams
Ex 6.4, 3 Important Deleted for CBSE Board 2023 Exams
Ex 6.4, 4 Deleted for CBSE Board 2023 Exams
Ex 6.4, 5 Important Deleted for CBSE Board 2023 Exams
Ex 6.4, 6 Important Deleted for CBSE Board 2023 Exams
Ex 6.4, 7 Important Deleted for CBSE Board 2023 Exams
Ex 6.4, 8 (MCQ) Important Deleted for CBSE Board 2023 Exams
Ex 6.4, 9 (MCQ) Deleted for CBSE Board 2023 Exams You are here
Last updated at Aug. 11, 2021 by Teachoo
Maths Crash Course - Live lectures + all videos + Real time Doubt solving!
Ex 6.4, 9 Tick the correct answer and justify : Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio (A) 2 : 3 (B) 4 : 9 (C) 81 : 16 (D) 16 : 81 Given, Ratio of sides of similar triangles = 4/9 We know that if two triangle are similar , ratio of areas is equal to the ratio of squares of corresponding sides . So, ( 1)/( 2)=( 1)^2/( 2)2 = (4/9)^2 = 16/81 Hence, option (D) is correct