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Question 6 - Ratio of Area of Similar Triangles - Chapter 6 Class 10 Triangles
Last updated at July 15, 2026 by Teachoo
Chapter 6 Class 10 Triangles
Serial order wise
- Ex 6.1
- Ex 6.2
- Ex 6.3
- Examples
- Theorems
- Case Based Questions (MCQ)
- NCERT Exemplar - MCQ
-
Ratio of Area of Similar Triangles
- Pythagoras Theorem and it's important questions
- Important questions of Triangle (in Geometry)
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Transcript
Question 6 Exercise 6.4 Chapter 6 Class 10 CBSE NCERT Maths Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians. Given: Let ABC ~ PQR Here AD is median Hence BD = CD = 1/2 BC Similarly, PS is median Hence QS = RS = 1/2 QR To prove: ( )/( )=( / )^2 Proof: Given ABC ~ PQR = Also, / = / / =2 /2 / = / In & = / = / ~ Hence / = / Now, since ABC PQR We know that if two triangles are similar, the ratio of their area is always equal to the square of the ratio of their corresponding side ( )/( ) = ( / )^2 ( )/( ) = ( / )^2 Hence proved
