Ex 5.4, 5 (iii) - Chapter 5 Class 8 Squares and Square Roots

Last updated at August 14, 2026 by

Find least number to be added to 252 so as to get perfect - Teachoo - Ex 5.4

part 2 - Ex 5.4, 5 (iii) - Ex 5.4 - Serial order wise - Chapter 5 Class 8 Squares and Square Roots
part 3 - Ex 5.4, 5 (iii) - Ex 5.4 - Serial order wise - Chapter 5 Class 8 Squares and Square Roots

Remove Ads

Transcript

Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iii) 252 Here, Remainder = 27 Since remainder is not 0, So, 252 is not a perfect square We need to find the least number that must be added to 252 so as to get a perfect square Now, Thus, we add 162 – 252 to the number ∴ Number to added = 162 − 252 = 256 – 252 = 4 Thus, Perfect square = 252 + 4 Let’s check Thus, we add 4 to 252 to get a perfect square. Perfect square = 256 & Square root of 256 = 16

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.