Ex 5.4, 4 (v) - Chapter 5 Class 8 Squares and Square Roots
Last updated at April 16, 2024 by Teachoo
Ex 5.4
Ex 5.4, 1 (i)
Ex 5.4, 1 (ii) Important
Ex 5.4, 1 (iii)
Ex 5.4, 1 (iv) Important
Ex 5.4, 1 (v)
Ex 5.4, 1 (vi) Important
Ex 5.4, 1 (vii)
Ex 5.4, 1 (viii) Important
Ex 5.4, 1 (ix)
Ex 5.4, 1 (x) Important
Ex 5.4, 1 (xi)
Ex 5.4, 1 (xii)
Ex 5.4, 2 (i)
Ex 5.4, 2 (ii) Important
Ex 5.4, 2 (iii)
Ex 5.4, 2 (iv)
Ex 5.4, 2 (v) Important
Ex 5.4, 3 (i)
Ex 5.4, 3 (ii) Important
Ex 5.4, 3 (iii)
Ex 5.4, 3 (iv) Important
Ex 5.4, 3 (v)
Ex 5.4, 4 (i) Important
Ex 5.4, 4 (ii)
Ex 5.4, 4 (iii) Important
Ex 5.4, 4 (iv)
Ex 5.4, 4 (v) Important You are here
Ex 5.4, 5 (i)
Ex 5.4, 5 (ii)
Ex 5.4, 5 (iii) Important
Ex 5.4, 5 (iv)
Ex 5.4, 5 (v) Important
Ex 5.4, 6
Ex 5.4, 7
Ex 5.4, 8 Important
Ex 5.4, 9 Important
Transcript
Ex 5.4, 4 Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (v) 4000 Finding square root of 4000 by long division Here, Remainder = 31 Since remainder is not 0, So, 4000 is not a perfect square We need to find the least number that must be subtracted from 4000 so as to get a perfect square Thus, we subtract 31 (remainder) from 4000 to get a perfect square. ∴ Perfect square = 4000 − 31 Perfect square = 3969 Also, If we do long division with 3969 We get 63 as square root ∴ Square root of 3969 = 63
