Ex 5.4, 5 (iv) - Chapter 5 Class 8 Squares and Square Roots

Last updated at August 8, 2026 by

Ex 5.4, 5 - Find least number to be added to 1825 so as to get perfect - Ex 5.4

part 2 - Ex 5.4, 5 (iv) - Ex 5.4 - Serial order wise - Chapter 5 Class 8 Squares and Square Roots
part 3 - Ex 5.4, 5 (iv) - Ex 5.4 - Serial order wise - Chapter 5 Class 8 Squares and Square Roots

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Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iv) 1825 Here, Remainder = 61 Since remainder is not 0, So, 1825 is not a perfect square We need to find the least number that must be added to 1825 so as to get a perfect square Now, Thus, we add 432 – 1825 to the number ∴ Number to added = 432 − 1825 = 1849 – 1825 = 24 Thus, Perfect square = 1825 + 24 Let’s check Thus, we add 24 to 1825 to get a perfect square. Perfect square = 1849 & Square root of 1849 = 43

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