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Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 10

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 11
Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 12

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Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iv) 1825Rough 81 × 1 = 81 82 × 2 = 164 83 × 3 = 249 Here, Remainder = 61 Since remainder is not 0, So, 1825 is not a perfect square We need to find the least number that must be added to 1825 so as to get a perfect square Now, Thus, we add 432 – 1825 to the number ∴ Number to added = 432 − 1825 = 1849 – 1825 = 24 Thus, Perfect square = 1825 + 24 Let’s check Thus, we add 24 to 1825 to get a perfect square. Perfect square = 1849 & Square root of 1849 = 43 Rough 81 × 1 = 81 82 × 2 = 164 83 × 3 = 249

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.