# Ex 6.4, 4 (iv) - Chapter 6 Class 8 Squares and Square Roots

Last updated at Aug. 31, 2021 by Teachoo

Last updated at Aug. 31, 2021 by Teachoo

Transcript

Ex 6.4, 4 Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iv) 825 Finding square root of 825 by long division Here, Remainder = 41 Since remainder is not 0, So, 825 is not a perfect square We need to find the least number that must be subtracted from 825 so as to get a perfect square Thus, we subtract 41 (remainder) from 825 to get a perfect square. ∴ Perfect square = 825 − 41 Perfect square = 784 Also, If we do long division with 784 We get 28 as square root ∴ Square root of 784 = 28

Ex 6.4

Ex 6.4, 1 (i)

Ex 6.4, 1 (ii)

Ex 6.4, 1 (iii)

Ex 6.4, 1 (iv)

Ex 6.4, 1 (v)

Ex 6.4, 1 (vi)

Ex 6.4, 1 (vii)

Ex 6.4, 1 (viii)

Ex 6.4, 1 (ix)

Ex 6.4, 1 (x)

Ex 6.4, 1 (xi)

Ex 6.4, 1 (xii)

Ex 6.4, 2 (i)

Ex 6.4, 2 (ii)

Ex 6.4, 2 (iii)

Ex 6.4, 2 (iv)

Ex 6.4, 2 (v)

Ex 6.4, 3 (i)

Ex 6.4, 3 (ii)

Ex 6.4, 3 (iii)

Ex 6.4, 3 (iv)

Ex 6.4, 3 (v)

Ex 6.4, 4 (i) Important

Ex 6.4, 4 (ii)

Ex 6.4, 4 (iii)

Ex 6.4, 4 (iv) You are here

Ex 6.4, 4 (v)

Ex 6.4, 5 (i) Important

Ex 6.4, 5 (ii)

Ex 6.4, 5 (iii)

Ex 6.4, 5 (iv)

Ex 6.4, 5 (v)

Ex 6.4, 6

Ex 6.4, 7 Important

Ex 6.4, 8 Important

Ex 6.4, 9 Important

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.