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Ex 5.4, 4 (iii) - Chapter 5 Class 8 Squares and Square Roots
Last updated at July 20, 2023 by Teachoo
Ex 5.4
Ex 5.4, 1 (i)
Ex 5.4, 1 (ii) Important
Ex 5.4, 1 (iii)
Ex 5.4, 1 (iv) Important
Ex 5.4, 1 (v)
Ex 5.4, 1 (vi) Important
Ex 5.4, 1 (vii)
Ex 5.4, 1 (viii) Important
Ex 5.4, 1 (ix)
Ex 5.4, 1 (x) Important
Ex 5.4, 1 (xi)
Ex 5.4, 1 (xii)
Ex 5.4, 2 (i)
Ex 5.4, 2 (ii) Important
Ex 5.4, 2 (iii)
Ex 5.4, 2 (iv)
Ex 5.4, 2 (v) Important
Ex 5.4, 3 (i)
Ex 5.4, 3 (ii) Important
Ex 5.4, 3 (iii)
Ex 5.4, 3 (iv) Important
Ex 5.4, 3 (v)
Ex 5.4, 4 (i) Important
Ex 5.4, 4 (ii)
Ex 5.4, 4 (iii) Important You are here
Ex 5.4, 4 (iv)
Ex 5.4, 4 (v) Important
Ex 5.4, 5 (i)
Ex 5.4, 5 (ii)
Ex 5.4, 5 (iii) Important
Ex 5.4, 5 (iv)
Ex 5.4, 5 (v) Important
Ex 5.4, 6
Ex 5.4, 7
Ex 5.4, 8 Important
Ex 5.4, 9 Important
Transcript
Ex 5.4, 4 Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iii) 3250 Finding square root of 3250 by long division Here, Remainder = 1 Since remainder is not 0, So, 3250 is not a perfect square Rough 106 × 6 = 636 107 × 7 = 749 108 × 8 = 864 We need to find the least number that must be subtracted from 3250 so as to get a perfect square Thus, we subtract 1 (remainder) from 3250 to get a perfect square. ∴ Perfect square = 3250 − 1 Perfect square = 3249 Also, If we do long division with 3249 We get 57 as square root ∴ Square root of 3249 = 57
