# Ex 6.4, 5 (ii) - Chapter 6 Class 8 Squares and Square Roots

Last updated at Aug. 31, 2021 by Teachoo

Last updated at Aug. 31, 2021 by Teachoo

Transcript

Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (ii) 1750Rough 81 × 1 = 81 82 × 2 = 164 Here, Remainder = 69 Since remainder is not 0, So, 1750 is not a perfect square We need to find the least number that must be added to 1750 so as to get a perfect square Now, Thus, we add 422 – 1750 to the number ∴ Number to added = 422 − 1750 = 1764 – 1750 = 14 Thus, Perfect square = 1750 + 14 Let’s check Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42 Rough 81 × 1 = 81 82 × 2 = 164 Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42

Ex 6.4

Ex 6.4, 1 (i)

Ex 6.4, 1 (ii)

Ex 6.4, 1 (iii)

Ex 6.4, 1 (iv)

Ex 6.4, 1 (v)

Ex 6.4, 1 (vi)

Ex 6.4, 1 (vii)

Ex 6.4, 1 (viii)

Ex 6.4, 1 (ix)

Ex 6.4, 1 (x)

Ex 6.4, 1 (xi)

Ex 6.4, 1 (xii)

Ex 6.4, 2 (i)

Ex 6.4, 2 (ii)

Ex 6.4, 2 (iii)

Ex 6.4, 2 (iv)

Ex 6.4, 2 (v)

Ex 6.4, 3 (i)

Ex 6.4, 3 (ii)

Ex 6.4, 3 (iii)

Ex 6.4, 3 (iv)

Ex 6.4, 3 (v)

Ex 6.4, 4 (i) Important

Ex 6.4, 4 (ii)

Ex 6.4, 4 (iii)

Ex 6.4, 4 (iv)

Ex 6.4, 4 (v)

Ex 6.4, 5 (i) Important

Ex 6.4, 5 (ii) You are here

Ex 6.4, 5 (iii)

Ex 6.4, 5 (iv)

Ex 6.4, 5 (v)

Ex 6.4, 6

Ex 6.4, 7 Important

Ex 6.4, 8 Important

Ex 6.4, 9 Important

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.