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Ex 6.4, 5 (ii) - Chapter 6 Class 8 Squares and Square Roots

Last updated at March 22, 2023 by

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 4

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 5
Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 6

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Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (ii) 1750Rough 81 × 1 = 81 82 × 2 = 164 Here, Remainder = 69 Since remainder is not 0, So, 1750 is not a perfect square We need to find the least number that must be added to 1750 so as to get a perfect square Now, Thus, we add 422 – 1750 to the number ∴ Number to added = 422 − 1750 = 1764 – 1750 = 14 Thus, Perfect square = 1750 + 14 Let’s check Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42 Rough 81 × 1 = 81 82 × 2 = 164 Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.