Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 4

Advertisement

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 5

Advertisement

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 6

  1. Chapter 6 Class 8 Squares and Square Roots
  2. Serial order wise

Transcript

Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (ii) 1750Rough 81 × 1 = 81 82 × 2 = 164 Here, Remainder = 69 Since remainder is not 0, So, 1750 is not a perfect square We need to find the least number that must be added to 1750 so as to get a perfect square Now, Thus, we add 422 – 1750 to the number ∴ Number to added = 422 − 1750 = 1764 – 1750 = 14 Thus, Perfect square = 1750 + 14 Let’s check Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42 Rough 81 × 1 = 81 82 × 2 = 164 Thus, we add 14 to 1750 to get a perfect square. Perfect square = 1764 & Square root of 1764 = 42

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.