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Ex 6.4

Ex 6.4, 1 (i)

Ex 6.4, 1 (ii) Important

Ex 6.4, 1 (iii)

Ex 6.4, 1 (iv) Important

Ex 6.4, 1 (v)

Ex 6.4, 1 (vi) Important

Ex 6.4, 1 (vii)

Ex 6.4, 1 (viii) Important

Ex 6.4, 1 (ix)

Ex 6.4, 1 (x) Important

Ex 6.4, 1 (xi)

Ex 6.4, 1 (xii)

Ex 6.4, 2 (i)

Ex 6.4, 2 (ii) Important

Ex 6.4, 2 (iii)

Ex 6.4, 2 (iv)

Ex 6.4, 2 (v) Important

Ex 6.4, 3 (i)

Ex 6.4, 3 (ii) Important

Ex 6.4, 3 (iii)

Ex 6.4, 3 (iv) Important

Ex 6.4, 3 (v)

Ex 6.4, 4 (i) Important

Ex 6.4, 4 (ii)

Ex 6.4, 4 (iii) Important

Ex 6.4, 4 (iv)

Ex 6.4, 4 (v) Important

Ex 6.4, 5 (i)

Ex 6.4, 5 (ii)

Ex 6.4, 5 (iii) Important

Ex 6.4, 5 (iv)

Ex 6.4, 5 (v) Important

Ex 6.4, 6

Ex 6.4, 7 You are here

Ex 6.4, 8 Important

Ex 6.4, 9 Important

Last updated at March 23, 2023 by Teachoo

Ex 6.4, 7 In a right triangle ABC, ∠B = 90°. (a) If AB = 6 cm, BC = 8 cm, find ACHypotenuse is the side opposite to right angle. Given, ∠B = 90° AB = 6 cm BC = 8 cm In right angled triangle ∆ABC, Using Pythagoras theorem, (Hypotenuse)2 = (Base)2 + (Perpendicular)2 AC2 = BC2 + AB2 AC2 = 82 + 62 AC2 = 64 + 36 AC2 = 100 AC = √100 Finding Square root of 100 by Prime factorization :- We see that, 100 = 2 × 2 × 5 × 5 ∴ √100 = 2 × 5 = 10 Therefore, AC = 10 cm Ex 6.4, 7 In a right triangle ABC, ∠B = 90°. (b) If AC = 13 cm, BC = 5 cm, find ABHypotenuse is the side of the triangle opposite to the right angle. Given, ∠B = 90° AC = 13 cm BC = 5 cm In ∆ABC right − angled at B, Using Pythagoras theorem, Ex 6.4, 7 In a right triangle ABC, ∠B = 90°. (b) If AC = 13 cm, BC = 5 cm, find ABHypotenuse is the side opposite to right angle. Given, ∠B = 90° AC = 13 cm BC = 5 cm In right angled triangle ∆ABC, Using Pythagoras theorem, (Hypotenuse)2 = (Base)2 + (Perpendicular)2 AC2 = BC2 + AB2 132 = 52 + AB2 AB2 = 132 – 52 AB2 = 169 – 25 AB2 = 144 AB = √144 Finding Square root of 144 by Prime factorization :- We see that, 144 = 2 × 2 × 2 × 2 × 3 × 3 ∴ √144 = 2 × 2 × 3 = 12 Therefore, AB = 12 cm