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Ex 6.4, 5 (iii) - Chapter 6 Class 8 Squares and Square Roots

Last updated at March 22, 2023 by

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 7

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 8
Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 9

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Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iii) 252Rough 24 × 4 = 96 25 × 5 = 125 26 × 6 = 156 Here, Remainder = 27 Since remainder is not 0, So, 252 is not a perfect square We need to find the least number that must be added to 252 so as to get a perfect square Now, Thus, we add 162 – 252 to the number ∴ Number to added = 162 − 252 = 256 – 252 = 4 Thus, Perfect square = 252 + 4 Let’s check Thus, we add 4 to 252 to get a perfect square. Perfect square = 256 & Square root of 256 = 16 Rough 24 × 4 = 96 25 × 5 = 125 26 × 6 = 156

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.