Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 5.4, 5 (iii) - Chapter 5 Class 8 Squares and Square Roots
Last updated at July 20, 2023 by Teachoo
Ex 5.4
Ex 5.4, 1 (i)
Ex 5.4, 1 (ii) Important
Ex 5.4, 1 (iii)
Ex 5.4, 1 (iv) Important
Ex 5.4, 1 (v)
Ex 5.4, 1 (vi) Important
Ex 5.4, 1 (vii)
Ex 5.4, 1 (viii) Important
Ex 5.4, 1 (ix)
Ex 5.4, 1 (x) Important
Ex 5.4, 1 (xi)
Ex 5.4, 1 (xii)
Ex 5.4, 2 (i)
Ex 5.4, 2 (ii) Important
Ex 5.4, 2 (iii)
Ex 5.4, 2 (iv)
Ex 5.4, 2 (v) Important
Ex 5.4, 3 (i)
Ex 5.4, 3 (ii) Important
Ex 5.4, 3 (iii)
Ex 5.4, 3 (iv) Important
Ex 5.4, 3 (v)
Ex 5.4, 4 (i) Important
Ex 5.4, 4 (ii)
Ex 5.4, 4 (iii) Important
Ex 5.4, 4 (iv)
Ex 5.4, 4 (v) Important
Ex 5.4, 5 (i)
Ex 5.4, 5 (ii)
Ex 5.4, 5 (iii) Important You are here
Ex 5.4, 5 (iv)
Ex 5.4, 5 (v) Important
Ex 5.4, 6
Ex 5.4, 7
Ex 5.4, 8 Important
Ex 5.4, 9 Important
Transcript
Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (iii) 252 Here, Remainder = 27 Since remainder is not 0, So, 252 is not a perfect square We need to find the least number that must be added to 252 so as to get a perfect square Now, Thus, we add 162 – 252 to the number ∴ Number to added = 162 − 252 = 256 – 252 = 4 Thus, Perfect square = 252 + 4 Let’s check Thus, we add 4 to 252 to get a perfect square. Perfect square = 256 & Square root of 256 = 16
