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Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 13

Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 14
Ex 6.4, 5 - Chapter 6 Class 8 Squares and Square Roots - Part 15


Transcript

Ex 6.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (v) 6412Rough 160 × 0 = 325 161 × 1 = 161 Here, Remainder = 12 Since remainder is not 0, So, 6412 is not a perfect square We need to find the least number that must be added to 6412 so as to get a perfect square Now, Thus, we add 812 – 6412 to the number ∴ Number to added = 812 − 6412 = 6561 – 6412 = 149 Thus, Perfect square = 6412 + 149 Let’s check Thus, we add 149 to 6412 to get a perfect square. Perfect square = 6561 & Square root of 6561 = 81 Rough 160 × 0 = 325 161 × 1 = 161

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.