Example 21 - Factorize 4x2 + y2 + z2 - 4xy - 2yz + 4xz - Examples

  1. Class 9
  2. Important Questions for Exam - Class 9
Ask Download

Transcript

Example 21 Factorize 4x2 + y2 + z2 – 4xy – 2yz + 4xz. 4x2 + y2 + z2 – 4xy – 2yz + 4xz = 22 x2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + y2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + z2 – 4xy – 2yz + 4xz = (2x)2 + (–y)2 + (z)2 + 2(2x)(–y) + 2(–y)(z) + 2(2x)(z) Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac where a = 2x, b= –y , c = z = (2x + (–y) + z)2 = (2x – y + z)2 = (2x – y + z)(2x – y + z)

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.