Ex 2.3, 1 (i) - Chapter 2 Class 9 Polynomials (Important Question)

Last updated at July 20, 2026 by

Ex 2.3, 1 (i) - Determine which polynomials has (x + 1) as factor - Ex 2.3

part 2 - Ex 2.3, 1 (i) - Ex 2.3 - Serial order wise - Chapter 2 Class 9 Polynomials

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Ex 2.3, 1 Determine which of the following polynomials has (x + 1) a factor: (i) x3 + x2 + x + 1 Finding remainder when x3 + x2 + x + 1 is divided by x + 1 Step 1: Put Divisor = 0 x + 1 = 0 x = 1 Step 2: Let p(x) = x3 + x2 + x + 1 Putting x = 1 p( 1) = ( 1)3 + ( 1)2 + ( 1) + 1 = 1 + 1 1 + 1 = 0 Thus, Remainder = p( 1) = 0 Since remainder is zero, x + 1 is a factor of x3 + x2 + x + 1

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