Question 2 - Chapter 2 Class 9 Polynomials (Important Question)

Last updated at July 20, 2026 by

Example 7 - Divide the polynomial 3x4 - 4x3 - 3x - 1 by x - 1 - Remainder Theoram

Example 7 - Chapter 2 Class 9 Polynomials - Part 2

Example 7 - Chapter 2 Class 9 Polynomials - Part 3

Remove Ads

Transcript

Question 2 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Question 2 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.