Another Peek beyond the Point - Chapter 4 Class 7 (Ganita Prakash II)

Master Another Peek beyond the Point - Chapter 4 Class 7 (Ganita Prakash II) with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

NCERT Solutions

Another Peek beyond the Point - Chapter 4 Class 7 (Ganita Prakash II) – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Figure it out - Page 73

10 questions

Question 1

(a) Recall that a tenth is 0.1, a hundredth is 0.01, and so on. Find the following products in tenths, hundredths and so on: (a) 6 × 4 tenths = 24 tenthsNow,
6 × 4 tenth = 6 × 4/10
= 6 × 0.4

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Question 2

(a) Find the products: (a) 27.34 × 6Need to find
27.34 × 6

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Question 3

Thejus needs 1.65 m of cloth for a shirt. How many metres of cloth are needed for 3 shirts?Now,
Cloth needed for 1 shirt = 1.65 m

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Question 4

Meenu bought 4 notebooks and 3 erasers. The cost of each book was ₹15.50 and each eraser was ₹2.75. How much did she spend in all?Let’s find cost of each
Notebook
Cost of 1 notebook = ₹ 15.50
Now,
Cost of 4 notebooks = 4 × 15.50
= 4 × 1550/100
= 4 × 155/10
= 4 × 155 × 𝟏/𝟏𝟎
= 620 × 1/10
= ₹ 62
Eraser
Cost of 1 eraser = ₹ 2.75
Now,
Cost of 3 erasers = 3 × 2.75
= 3 × 275/100
= 3 × 275 × 𝟏/𝟏𝟎𝟎
= 825 × 1/100
= ₹ 8.25
Thus,
Total amount spent = Cost of 4 notebooks + Cost of 3 erasers
= 62 + 8.25
= 62 + 825/100
= (62 × 100 + 825)/100
= (𝟔𝟐𝟎𝟎 + 𝟖𝟐𝟓)/𝟏𝟎𝟎
= 7025/100
= ₹ 70.25

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Question 5

Thus,
Total amount spent = Cost of 4 notebooks + Cost of 3 erasers
= 62 + 8.25
= 62 + 825/100
= (62 × 100 + 825)/100
= (𝟔𝟐𝟎𝟎 + 𝟖𝟐𝟓)/𝟏𝟎𝟎
= 7025/100
= ₹ 70.25
Since we need to write the answer in cm
We convert all units to cm before
Since
10 mm = 1 cm
1 mm = 1/10 cm

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Question 6

The price of 1 kg of oranges is ₹56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?First let us answer the second part of the question

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Question 7

Dwarakanath purchases notebooks at a wholesale price of ₹23.6 per piece and sells each notebook at ₹30/-. How much profit does he make if he sells 50 books in a week?First, let us find Profit on 1 book
Now,
Profit on 1 book = Selling Price of 1 book – Cost price of 1 book
= 30 – 23.6
= 30 – 236/10
= (30 × 10 − 236)/10
= (𝟑𝟎𝟎 − 𝟐𝟑𝟔)/𝟏𝟎
= 64/10
= ₹ 6.4
We need to find How much profit does he make if he sells 50 books in a week

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Question 8

Given that 18 × 12 = 216, find the products: (a) 18 × 1.2 (b) 18 × 0.12 (c) 1.8 × 1.2 (d) 0.18 × 0.12 (e) 0.018 × 0.012 (f) 1.8 × 12 In which of the cases above is the product less than 1?Given that
18 × 12 = 216

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Question 9

In which of the following multiplications is the product less than 1? Can you find the answer without actually doing the multiplications? (a) 7 × 0.6 (b) 0.7 × 0.6 (c) 0.7 × 6 (d) 0.07 × 0.06The rule we follow here is
If you multiply two numbers that are both smaller than 1 (like 0.5 or 0.7), the answer will always be smaller than 1

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Question 10

Multiplying the following numbers by 10, 100 and 1000 to complete the table.We follow this logic
× 10: Move decimal 1 step right
× 100: Move decimal 2 steps right
× 1000: Move decimal 3 steps right

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Figure it out - Page 83

4 questions

Question 1

(a) Find the quotient by converting the denominator into 1, 10, 100 or 1000 and verify the solution by the long division method (division by place value). (a) 18/5Converting denominator
Since 5 × 2 = 10, we multiply and divide by 2
Thus,
18/5=𝟏𝟖/𝟓 ×𝟐/𝟐
=(18 × 2)/(5 × 2)
=(18 × 2)/10
=𝟏𝟖 × 𝟐 × 𝟏/𝟏𝟎
=36 × 1/10
=𝟑.𝟔

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Question 2

(a) Choose the correct answer: (a) 1526/4 = (i) 38.15 (ii) 380.15 (iii) 381.5 (iv) 381.05Let’s do long division

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Question 3

What is the quotient? (a) 132 ÷ 4 = (b) 13.2 ÷ 4 = (c) 1.32 ÷ 4 = (d) 0.132 ÷ 4 = Let’s first find 132 ÷ 4 and then we can all the options by moving decimal point

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Question 4

What is the quotient? (a) 126 ÷ 8 = (b) 12.6 ÷ 8 = (c) 1.26 ÷ 8 = (d) 0.126 ÷ 8 = (e) 0.0126 ÷ 8 =Let’s first find 126 ÷ 8 and then we can all the options by moving decimal point

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Figure it out - Page 86, 87

10 questions

Question 1

(a) Express the following fractions in decimal form: (a) 2/5Here, we can convert denominator into 10
By Multiplying and Dividing by 2

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Question 2

(a) Find the quotients: (a) 24.86 ÷ 1.2Now,
24.86 ÷ 1.2 = 24.86/1.2
=24.86 ×1/1.2
Removing decimal point
=2486/100 ×1/(12/10)
=𝟐𝟒𝟖𝟔/𝟏𝟎𝟎 ×𝟏𝟎/𝟏𝟐
=2486/10 ×1/12
=𝟐𝟒𝟖𝟔/𝟏𝟐 ×𝟏/𝟏𝟎
.
=1243/6 ×1/10
=𝟏𝟐𝟒𝟑/𝟔𝟎
Now, we do division like we usually do

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Question 3

Evaluate the following using the information 156 × 12 = 1872. (a) 15.6 × 1.2 = __________ (b) 187.2 ÷ 1.2 = __________ (c) 18.72 ÷ 15.6 = __________ (d) 0.156 × 0.12 = __________We use the "count the decimal places" trick here
(a) 15.6 × 1.2
Since it is multiplication, we add the decimal places in both numbers

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Question 4

(a) Evaluate the following: (a) 25 ÷ ______ = 0.025We can write this as
25/🔲=0.025
25/🔲=25/1000
25 × 1000=🔲 × 25
(25 × 1000)/25=🔲
🔲=(25 × 1000)/25
🔲=𝟏𝟎𝟎𝟎

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Question 5

Find the quotient: (a) 2.46 ÷ 1.5 = (b) 2.46 ÷ 0.15 = (c) 2.46 ÷ 0.015 = Is the quotient obtained in 24.6 ÷ 1.5 the same as the quotient obtained in 2.46 ÷ 0.15? Let’s first find 246 ÷ 15 and then we can all the options by moving decimal point

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Question 6

A 4 m long wooden block has to be cut into 5 pieces of equal length. What is the length of each piece?Now,
Length of each piece = (𝑇𝑜𝑡𝑎𝑙 𝑙𝑒𝑛𝑔𝑡ℎ 𝑜𝑓 𝑤𝑜𝑜𝑑𝑒𝑛 𝑏𝑙𝑜𝑐𝑘)/(𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑝𝑖𝑒𝑐𝑒𝑠)
= 𝟒/𝟓
Making denominator 10 as 5 × 2 = 10
Multiplying and dividing by 2
= 𝟒/𝟓 ×𝟐/𝟐
= (4 × 2)/(5 × 2)
= 𝟖/𝟏𝟎
Now,
Length of each piece = (𝑇𝑜𝑡𝑎𝑙 𝑙𝑒𝑛𝑔𝑡ℎ 𝑜𝑓 𝑤𝑜𝑜𝑑𝑒𝑛 𝑏𝑙𝑜𝑐𝑘)/(𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑝𝑖𝑒𝑐𝑒𝑠)
= 𝟒/𝟓
Making denominator 10 as 5 × 2 = 10
Multiplying and dividing by 2
= 𝟒/𝟓 ×𝟐/𝟐
= (4 × 2)/(5 × 2)
= 𝟖/𝟏𝟎
= 08/10
= 0.8 m

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Question 7

If the perimeter of a regular polygon with 12 sides is 208.8 cm, what is the length of its side?We know that
Perimeter of regular polygon = Length of each side × Number of sides
(𝑃𝑒𝑟𝑖𝑚𝑒𝑡𝑒𝑟 𝑜𝑓 𝑅𝑒𝑔𝑢𝑙𝑎𝑟 𝑃𝑜𝑙𝑦𝑔𝑜𝑛)/(𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑠𝑖𝑑𝑒𝑠)= Length of each side
Length of each side = (𝑷𝒆𝒓𝒊𝒎𝒆𝒕𝒆𝒓 𝒐𝒇 𝑹𝒆𝒈𝒖𝒍𝒂𝒓 𝑷𝒐𝒍𝒚𝒈𝒐𝒏)/(𝑵𝒖𝒎𝒃𝒆𝒓 𝒐𝒇 𝒔𝒊𝒅𝒆𝒔)

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Question 8

3 litres of watermelon juice is shared among 8 friends equally. How much watermelon juice will each get? Express the quantity of juice in millilitres.Since we want our answer in mililiters
We convert our given values into mililiters first

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Question 9

A car covers 234.45 km using 12.6 litres of petrol. What is the distance travelled per litre?Now,
Distance travelled per liter = (𝑇𝑜𝑡𝑎𝑙 𝑑𝑖𝑠𝑡𝑎𝑛𝑐𝑒)/(𝐴𝑚𝑜𝑢𝑛𝑡 𝑜𝑓 𝑝𝑒𝑡𝑟𝑜𝑙 𝑢𝑠𝑒𝑑 (𝑖𝑛 𝑙𝑖𝑡𝑒𝑟𝑠))
= (𝟐𝟑𝟒.𝟒𝟓)/(𝟏𝟐.𝟔)
Removing decimal points
= 234.45 × 1/12.6
= 23445/100 × 10/126
= 23445/10 × 1/126
= 𝟐𝟑𝟒𝟒𝟓/𝟏𝟐𝟔𝟎
Now, we do long division

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Question 10

13.5 kg of flour (aata) was distributed equally among 15 students. How much flour did each student receive? What pattern do you observe? Why are 2 and 5 related in this way? We will answer this one-by-one

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Figure it out - Page 93, 94, 95

11 questions

Question 1

How could we fix this?
To get rid of those 3 extra days, future humans might decide on a new rule. For example:
The " 3200 Rule": If we skip the leap year every 3,200 years (years that are normally leap years like 3200,6400 , and 9600 ), we would subtract those 3 days and be almost perfectly back on track!
To find out which is cheaper,
we need to find the cost per gram

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Question 2

Write the decimal number at the arrow mark:Let’s do it one by one
First Number Line

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Question 3

Shyamala bought 3 kg bananas at ₹30/- per kg. She counted 35 bananas in all. She sells each banana for ₹5/-. How much profit does she make selling all the bananas? Now,
Profit = Selling Price – Cost Price

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Question 4

A teacher placed textbooks that are 2.5 cm thick on a bookshelf. The teacher wanted to place 80 textbooks on the shelf. The bookshelf is 160 cm long. How many books could be placed on the shelf? Was there any space left? If yes, how much?First, let us find how much space 80 textbooks take

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Question 5

Fill in the following blanks appropriately:We do it one by one
5.5 km
Given that
1 km = 1000 m

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Question 6

The following problem was set by Sridharacharya in his book, Patiganita. “ 6 1/4 is divided by 2 1/2 , and 60 1/4 is divided by 3 1/2 . Tell the quotients separately.” Can you try to solve it by converting the fractions into decimals?First, we convert fractions into decimals
Now,
𝟏/𝟒 = 0.25 and 𝟏/𝟐 = 0.5

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Question 7

(a) Fill the boxes in at least 2 different ways: (a) × = 2.4We know
6 × 4 = 24

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Question 8

Find the following quotients given that 756 ÷ 36 = 21: (a) 75.6 ÷ 3.6 (b) 7.56 ÷ 0.36 (c) 756 ÷ 0.36 (d) 75.6 ÷ 360 (e) 7560 ÷ 3.6 (f) 7.56 ÷ 0.36 Given
756 ÷ 36 = 21
Now, while dividing we follow these rules
Calculate the "Gap": (Decimal places in Numerator) – (Decimal places in Denominator).
The Move:
If the Gap is Positive (+) → Move decimal to the Left.
If the Gap is Negative (-) → Move decimal to the Right.

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Question 9

Find the missing cells if each cell represents a ÷ b:While dividing we follow these rules
Calculate the "Gap": (Decimal places in Numerator) – (Decimal places in Denominator).
The Move:
If the Gap is Positive (+) → Move decimal to the Left.
If the Gap is Negative (-) → Move decimal to the Right.

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Question 10

Using the digits 2, 4, 5, 8, and 0 fill the boxes to get the: (a) maximum product To get the largest product,
we put the largest digits in the highest place values (the tens and the ones).

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Question 11

Sort the following expressions in increasing order: (a) 245.05 × 0.942368 (b) 245.05 × 7.9682 (c) 245.05 ÷ 7.9682 (d) 245.05 ÷ 0.942368 (e) 245.05 (f) 7.9682 We can solve this by looking at how the operations change the base number (245.05).
Dividing by a number larger than 1 makes a number smaller
Multiplying by a number less than 1 makes it smaller
Dividing by a number less than 1 makes it larger
Multiplying by a number larger than 1 makes it larger

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Why Learn This With Teachoo?

Another Peek Beyond the Point is Chapter 4 of NCERT Class 7 Ganita Prakash Part 2. It extends the decimal ideas learned in Part 1 to multiplication and division. Students investigate place-value patterns, long division, decimal divisors, special cases and relationships among dividend, divisor and quotient. Teachoo offers concept-wise learning and step-by-step Figure it out solutions to help students understand the reasoning behind every decimal shift.

Multiplication and division of decimals

The chapter starts with a quick recap of decimal place value and operations. In decimal multiplication, students first connect the calculation with fractions or place values. Multiplying as whole numbers and then locating the decimal point is a useful procedure, but the number of decimal places must be justified by the factors’ place values.

“Is the Product Always Greater than the Numbers Multiplied?” challenges a common belief formed from whole-number arithmetic. Multiplying a positive number by a value between zero and one makes it smaller. Multiplying by one leaves it unchanged, while multiplying by a number greater than one makes it larger. Estimating the likely product before calculation helps detect a misplaced decimal point.

Decimal division is developed through sharing, grouping and the inverse relationship with multiplication. Students use long division when the dividend contains a decimal. The decimal point in the quotient is placed in line with the point in the dividend when dividing by a whole number.

When the divisor is decimal, both dividend and divisor are multiplied by the same power of ten so that the divisor becomes a whole number. This transformation preserves the quotient because both quantities are scaled equally.

Special cases examine zero, one, powers of ten and divisions that produce terminating or continuing decimal expansions within the expected level. The relationship dividend = divisor × quotient + remainder supports checking. “Look Before You Leap!” emphasises estimation, operation choice and reasonableness before applying a procedure.

Topics covered on Teachoo

The chapter page includes:

  • quick recap of decimal concepts;

  • decimal multiplication;

  • comparison of a product with its factors;

  • Figure it out work on page 73;

  • decimal division;

  • division using long division;

  • Figure it out work on page 83;

  • division with a decimal divisor;

  • special cases of division;

  • dividend, divisor and quotient;

  • Figure it out work on pages 86–87;

  • Look Before You Leap; and

  • solutions for pages 93–95.

Learning outcomes

Students should be able to multiply and divide decimals with accurate place value, estimate a result’s magnitude and explain when a product or quotient becomes larger or smaller. They should convert a decimal divisor into a whole-number divisor without changing the quotient and check using the inverse operation. They should also solve money, measurement or rate problems in which the required operation must be inferred.

Why is this chapter important?

Decimal multiplication and division are used for prices, unit rates, measurements, area, speed, averages and scientific quantities. They also prepare students for percentages, ratios and algebraic calculations. Strong estimation prevents the most common and serious decimal error: an answer with the correct digits but the wrong magnitude.

The chapter reinforces the idea that operations depend on the numbers involved. Multiplication does not always increase, and division does not always decrease. Dividing a positive number by a decimal less than one can produce a larger quotient because more small groups fit into the original amount.

How Teachoo helps

Teachoo’s topic sequence allows students to master multiplication before division and whole-number divisors before decimal divisors. Solutions display intermediate steps, place-value changes and checks. Students can return to the exact subtopic causing difficulty instead of revising the whole chapter at once.

Before calculating, round the numbers and estimate a range for the answer. During multiplication, count place values rather than moving the decimal point by guesswork. During division, make the divisor whole by multiplying both dividend and divisor by the same power of ten. Finally, multiply the quotient by the divisor to check.

Common mistakes to avoid

Do not place the decimal point solely by counting digits in the final answer without understanding the factors. Never multiply only the divisor by 10 or 100; scale the dividend by the same amount. Keep zeros that serve as decimal placeholders during long division.

Do not assume that a quotient must be smaller than the dividend. Compare the divisor with one first. Division by zero is undefined.

Deeper reasoning and concept connections

Study Another Peek Beyond the Point (Ganita Prakash Part 2) through comparison and justification. Place two related examples side by side, identify the decisive difference and explain why one method works in each case. Then create a new example and a deliberate non-example. This forces the definition to do real work and exposes gaps that passive reading hides.

Students should also practise reversing questions. After solving for an answer, ask what question could have produced it, whether more than one answer is possible and which extra condition would make the result unique. Reverse reasoning develops flexibility and is especially useful for missing-value, assertion–reason and error-analysis questions. The goal is to understand the network of ideas, not merely the order of a textbook solution.

How to solve unfamiliar and competency-based questions

Begin by separating facts from conclusions. Facts are given by the question or a known property; conclusions must be derived. Draw or rewrite the problem so each fact has a visible place. If several methods are possible, prefer the one with fewer assumptions and an easy final check. Record intermediate results rather than doing everything mentally.

Competency questions often change context without changing mathematics. Replace names and story details with variables, shapes, sets or data values. After solving, restore the context and check feasibility: counts should be whole where required, lengths and areas should have suitable units, probabilities should lie between 0 and 1, and constructed figures should satisfy every stated condition.

What complete mastery looks like

For Another Peek Beyond the Point (Ganita Prakash Part 2), a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting Another Peek Beyond the Point (Ganita Prakash Part 2)?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in Another Peek Beyond the Point (Ganita Prakash Part 2)?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

How do you multiply decimal numbers?

Multiply using place value or as whole numbers, then place the decimal so the product reflects the combined decimal places of the factors. Check its size by estimation.

How do you divide by a decimal divisor?

Multiply both dividend and divisor by the same power of ten until the divisor is a whole number, then divide.

Why is estimation essential in this chapter?

It shows the expected magnitude of the result and quickly exposes many decimal-point errors.

Look before you calculate, track place value during the operation and verify the result with the inverse operation.