Ex 12.3, 5 (vii) - Chapter 12 Class 8 Factorisation
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 12.3, 5 Factorise the expressions and divide them as directed. (vii) 39๐ฆ^3(50๐ฆ^2 โ 98) รท 26๐ฆ^2 (5y + 7)We first factorise ใ39๐ฆใ^3 (50๐ฆ^2โ 98) = ใ39๐ฆใ^3 (2รใ25๐ฆใ^2 โ 2 ร 49) Taking 2 common = ใ39๐ฆใ^3ร2 (ใ25๐ฆใ^2โ49) = ใ78๐ฆใ^3 (ใ25๐ฆใ^2โ49) = ใ๐๐๐ใ^๐ [(ใ๐๐ใ^๐)โ(๐)^๐] = ใ78๐ฆใ^3 (5y โ 7) (5y + 7) Dividing 39๐ฆ^3(50๐ฆ^2 โ 98) รท 26๐ฆ^2 (5y + 7) = (39๐ฆ^3 (50๐ฆ^2 โ 98))/(26๐ฆ^2 (5๐ฆ + 7)) = (๐๐๐^๐ (๐๐ + ๐) (๐๐ โ ๐))/(๐๐๐^๐ (๐๐ + ๐)) = 78/26 ร ๐ฆ^3/๐ฆ^2 ร ((5๐ฆ + 7))/((5๐ฆ + 7)) ร (5y โ 7) = 3 ร y ร (5y โ7) = 3y (5y โ 7)
Ex 12.3
Ex 12.3, 1 (ii) Important
Ex 12.3, 1 (iii)
Ex 12.3, 1 (iv) Important
Ex 12.3, 1 (v)
Ex 12.3, 2 (i)
Ex 12.3, 2 (ii) Important
Ex 12.3, 2 (iii) Important
Ex 12.3, 2 (iv)
Ex 12.3, 2 (v) Important
Ex 12.3, 3 (i)
Ex 12.3, 3 (ii)
Ex 12.3, 3 (iii) Important
Ex 12.3, 3 (iv)
Ex 12.3, 3 (v) Important
Ex 12.3, 4 (i)
Ex 12.3, 4 (ii) Important
Ex 12.3, 4 (iii)
Ex 12.3, 4 (iv)
Ex 12.3, 4 (v) Important
Ex 12.3, 5 (i)
Ex 12.3, 5 (ii) Important
Ex 12.3, 5 (iii)
Ex 12.3, 5 (iv) Important
Ex 12.3, 5 (v)
Ex 12.3, 5 (vi)
Ex 12.3, 5 (vii) Important You are here
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo