Ex 12.3, 5 (iv) - Chapter 12 Class 8 Factorisation
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 12.3, 5 Factorise the expressions and divide them as directed. (iv) 4yz(๐ง^2 + 6z โ 16) รท 2y(z + 8)We first factorise 4yz (๐^๐+๐๐โ๐๐) By middle term splitting, = 4yz (๐ง^2โ๐๐+๐๐โ16) = 4yz [(๐ง^2โ2๐ง)+(8๐งโ16)] = 4yz [z (z โ 2) + 8 (z โ 2)] Taking (z โ 2) common, = 4yz (z โ 2) (z + 8) Splitting the middle term We need to find two numbers whose Sum = 6 Product = โ16 So, we write 6z = โ2z + 8z Dividing 4yz (๐ง^2+6๐งโ16)รท2๐ฆ (๐ง+8) = (4๐ฆ๐ง (๐ง^2 + 6๐ง โ 16))/(2๐ฆ (๐ง + 8)) = (๐๐๐ (๐ โ๐) (๐ + ๐))/(๐๐ (๐ + ๐)) = 4/2 ร ๐ฆ/๐ฆ ร z ร (z โ 2) ร ((๐ง + 8))/((๐ง + 8)) = 2 ร z ร (z โ 2) = 2z (๐ โ 2)
Ex 12.3
Ex 12.3, 1 (ii) Important
Ex 12.3, 1 (iii)
Ex 12.3, 1 (iv) Important
Ex 12.3, 1 (v)
Ex 12.3, 2 (i)
Ex 12.3, 2 (ii) Important
Ex 12.3, 2 (iii) Important
Ex 12.3, 2 (iv)
Ex 12.3, 2 (v) Important
Ex 12.3, 3 (i)
Ex 12.3, 3 (ii)
Ex 12.3, 3 (iii) Important
Ex 12.3, 3 (iv)
Ex 12.3, 3 (v) Important
Ex 12.3, 4 (i)
Ex 12.3, 4 (ii) Important
Ex 12.3, 4 (iii)
Ex 12.3, 4 (iv)
Ex 12.3, 4 (v) Important
Ex 12.3, 5 (i)
Ex 12.3, 5 (ii) Important
Ex 12.3, 5 (iii)
Ex 12.3, 5 (iv) Important You are here
Ex 12.3, 5 (v)
Ex 12.3, 5 (vi)
Ex 12.3, 5 (vii) Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo