1. Chapter 12 Class 8 Factorisation
  2. Serial order wise
  3. Ex 12.3
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Ex 12.3, 2 (ii) - Chapter 12 Class 8 Factorisation

Last updated at Dec. 16, 2024 by Teachoo

 

Transcript

Ex 12.3, 2 (Method 1) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^43๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4 = (3๐‘ฆ^4ร—๐‘ฆ^4 ) โˆ’ (4y^2ร—๐‘ฆ^4 )+(5ร—y^4) Taking ๐‘ฆ^4 common = ๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ 4๐‘ฆ^2+5) Dividing (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (๐‘ฆ^4 (3๐‘ฆ^4 โˆ’ ใ€–4๐‘ฆใ€—^4 + 5))/๐‘ฆ^4 = ๐Ÿ‘๐’š^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ + ๐Ÿ“ Ex 12.3, 2 (Method 2) Divide the given polynomial by the given monomial. (ii) (3๐‘ฆ^8 โ€“ 4๐‘ฆ^6 + 5๐‘ฆ^4) รท ๐‘ฆ^4 (3๐‘ฆ^8 โˆ’ 4๐‘ฆ^6 + 5๐‘ฆ^4)/๐‘ฆ^4 = (๐Ÿ‘๐’š^๐Ÿ–)/๐’š^๐Ÿ’ โˆ’ใ€–๐Ÿ’๐’šใ€—^๐Ÿ”/๐’š^๐Ÿ’ +(๐Ÿ“๐’š^๐Ÿ’)/๐’š^๐Ÿ’ = 3ร—๐‘ฆ^(8 โˆ’ 4)โˆ’ 4ร— ๐‘ฆ^(6 โˆ’ 4)+5ร—๐‘ฆ^(4 โˆ’ 4) = 3ร—๐‘ฆ^4โˆ’ 4ร— ๐‘ฆ^2+ใ€–5๐‘ฆใ€—^0 = ใ€–๐Ÿ‘๐’šใ€—^๐Ÿ’ โˆ’ ๐Ÿ’๐’š^๐Ÿ+๐Ÿ“ (๐ด๐‘  ๐‘Ž^๐‘š/๐‘Ž^๐‘› =๐‘Ž^(๐‘š โˆ’ n) ) (As ๐‘Ž^0=1)
  1. Chapter 12 Class 8 Factorisation
  2. Serial order wise

    3. Ex 12.3

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Chapter 12 Class 8 Factorisation
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo