Check sibling questions


Transcript

Ex 6.2, 1 (Method 1) Show that the function given by f (๐‘ฅ) = 3๐‘ฅ + 17 is strictly increasing on R. f(๐‘ฅ) = 3๐‘ฅ + 17 Finding fโ€™(๐’™) fโ€™(๐‘ฅ) = 3 Since fโ€™(๐’™) > 0 Hence, f is strictly increasing on R Ex 6.2, 1 (Method 2) Show that the function given by f (x) = 3x + 17 is strictly increasing on R. Let ๐‘ฅ1 and ๐‘ฅ2 be real numbers Such that ๐’™๐Ÿ < ๐’™2 Multiplying both sides by 3 3๐‘ฅ1 < 3 ๐‘ฅ2 Adding both sides by 17 3๐‘ฅ1 + 17 < 3๐‘ฅ2 + 17 f (๐’™๐Ÿ) < f ( ๐’™2) Hence, when x1 < x2 , f(x1) < f(x2) Thus, f(x) is strictly increasing on R.

  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo