Ex 13.3, 4 - Chapter 13 Class 12 Probability (Important Question)
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 13.3, 4 In answering a question on a multiple choice test, a student either knows the answer or guesses. Let 3/4 be the probability that he knows the answer and 1/4 be the probability that he guesses. Assuming that a student who guesses at the answer will be correct with probability 1/4. What is the probability that the student knows the answer given that he answered it correctly?Let A : student know the answer B : student guesses C : student answers correctly We need to find the Probability that the student knows the answer, if he answered it correctly i.e. P(A|C) P(A|C) = ("P(A)" ." P(C|A)" )/" P(A) . P(C|A) + P(B) P(C|B) " "P(A)" = Probability that student knows the answer = 𝟑/𝟒 "P(C|A)" = Probability that the student correctly, if he knows the answer = 1 "P(B)" = Probability that the student guesses the answer = 𝟏/𝟒 "P(C|B)" = Probability that the student correctly, if he guesses = 𝟏/𝟒 Putting values in formula, P(A|C) = (𝟑/𝟒 × 𝟏)/( 𝟏/𝟒 × 𝟏/𝟒 + 𝟑/𝟒 × 𝟏 ) = (1/4 × 3)/( 1/4 [ 1/4 + 3 ] ) = 3/( 1/4 + 3 ) = 3/( 13/4 ) = 12/13 Therefore, required probability is 𝟏𝟐/𝟏𝟑
Chapter 13 Class 12 Probability
Example 6
Ex 13.1, 10 (a) Important
Ex 13.1, 12 Important
Example 11 Important
Ex 13.2, 7 Important
Ex 13.2, 11 (i)
Ex 13.2, 14 Important
Example 17 Important
Example 18 Important
Example 20 Important
Example 21 Important
Ex 13.3, 2 Important
Ex 13.3, 4 Important You are here
Ex 13.3, 8 Important
Ex 13.3, 10 Important
Ex 13.3, 12 Important
Ex 13.3, 13 (MCQ) Important
Question 4 Important
Question 5 Important
Question 6
Question 7 Important
Question 8 Important
Question 3 Important
Question 6 Important
Question 11 Important
Question 15
Question 10 Important
Question 11 Important
Question 4 Important
Question 6 Important
Question 10 Important
Question 13 Important
Question 13
Example 23 Important
Question 2 Important
Question 4
Question 6 Important
Misc 7 Important
Misc 10 Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo