Question 3 - Examples - Chapter 2 Class 9 Polynomials
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 3 (Method 1) Find the remainder obtained on dividing ๐(๐ฅ)=๐ฅ^3+1 by ๐ฅ+1 Dividing ๐^๐+๐ by ๐+๐ Step 1: Putting Divisor = 0 x + 1 = 0 x = โ1 Step 2: Let ๐(๐ฅ)=๐ฅ^3+1 Putting x = โ1 ๐(โ๐)=ใ(โ๐)ใ^3+1 =โ1+1 =0 Thus, Remainder =๐(โ๐)=๐ Question 3 (Method 2) Find the remainder obtained on dividing ๐(๐ฅ)=๐ฅ^3+1 by ๐ฅ+1 By long division Hence, the remainder is 0
Examples
Example 1 (ii)
Example 1 (iii) Important
Example 2 (i)
Example 2 (ii)
Example 2 (iii)
Example 3 Important
Example 4
Example 5 Important
Example 6 Important
Example 7 Important
Example 8 Important
Example 9
Example 10 Important
Example 11 (i)
Example 11 (ii)
Example 12
Example 13 (i) Important
Example 13 (ii)
Example 14
Example 15
Example 16 Important
Example 17 (i)
Example 17 (ii)
Example 18 (i) Important
Example 18 (ii)
Example 19 Important
Example 20 Important
Question 1
Question 2 Important
Question 3 You are here
Question 4 Important
Question 5
About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo