Last updated at Dec. 16, 2024 by Teachoo
Question 7 Find the intercepts cut off by the plane 2x + y – z = 5. The equation of a plane with intercepts 𝑎, b, c on x, y, and z – axis respectively is 𝒙𝒂 + 𝒚𝒃 + 𝒛𝒄 = 1 Given, equation of plane is 2x + y – z = 5 Dividing by 5 2𝑥 + 𝑦 − 𝑧5 = 55 2𝑥5 + 𝑦5 − 𝑧5 = 1 𝑥 52 + 𝑦5 + 𝑧(−5) = 1 Comparing above equation with (1) a = 𝟓𝟐 , b = 5 , c = −5
Plane
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo