Supplementary Exercise Q4
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Supplementary Exercise Q4 Show that (i) the vectors ๐ โ = 2๐ ฬ โ ๐ ฬ + ๐ ฬ, ๐ โ = ๐ ฬ + 2๐ ฬ โ 3๐ ฬ, and ๐ โ = 3๐ ฬ โ 4๐ ฬ + 5๐ ฬ are coplanar. Three vectors ๐ โ, ๐ โ, ๐ โ are coplanar if [ ๐ โ, ๐ โ, ๐ โ ] = 0 Given, ๐ โ = 2๐ ฬ โ ๐ ฬ + ๐ ฬ ๐ โ = ๐ ฬ + 2๐ ฬ โ 3๐ ฬ ๐ โ = 3๐ ฬ โ 4๐ ฬ + 5๐ ฬ [๐ โ,๐,๐ โ ] = |โ 8(2&โ1&1@1&2&โ3@3&โ4&5)| = 2[(2ร5)โ(โ4รโ3)] โ (โ1) [(1ร5)โ(3รโ3) ] + 1[(1รโ4)โ(3ร2) ] = 2 [10โ12]+[5+9] + [โ4โ6] = โ4 + 14 โ 10 = 0 โด [๐ โ,๐,๐ โ ] = 0 Therefore, ๐ โ,๐ and ๐ โ are coplanar. Supplementary Exercise Q4 Show that (ii) the vectors ๐ โ = ๐ ฬ โ 2๐ ฬ + 3๐ ฬ, ๐ โ = โ2๐ ฬ + 3๐ ฬ โ 4๐ ฬ, and ๐ โ = ๐ ฬ โ 3๐ ฬ + 5๐ ฬ are coplanar Three vectors ๐ โ, ๐ โ, ๐ โ are coplanar if [ ๐ โ, ๐ โ, ๐ โ ] = 0 Given, ๐ โ = ๐ ฬ โ 2๐ ฬ + 3๐ ฬ ๐ โ = โ2๐ ฬ + 3๐ ฬ โ 4๐ ฬ ๐ โ = ๐ ฬ โ 3๐ ฬ + 5๐ ฬ [๐ โ,๐,๐ โ ] = |โ 8(1&โ2&3@โ2&3&โ4@1&โ3&5)| = 1[(3ร5)โ(โ3ร4) ] โ (โ2) [(โ2ร5)โ(1รโ4) ] + 3[(โ2รโ3)โ(1ร3) ] = 1 [15โ12]+[2(โ10โ(โ4)] + 3 [6โ3] = 1(3) + 2 (โ6) + 3 (3) = 3 โ 12 + 9 = 12 โ 12 = 0 โด [๐ โ,๐,๐ โ ] = 0 Therefore, ๐ โ,๐ and ๐ โ are coplanar.
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo