Last updated at Dec. 16, 2024 by Teachoo
Ex 12.2, 5 For the function f(x) = x100100 + x99100 +….+ x22 + x + 1. Prove that f’(1) = 100 f’(0) We have f (x) = 𝑥100100 + 𝑥9999 + …… + 𝑥22 + x + 1 f’ (x) = 1100 x100 + 199 x99 + …… + 12 x2 + x1 + 1′ f’ (x) = 1100 × 100x100 – 1 + 199 × 99x99 – 1 + … + 12 × 2x2 – 1 + 1.x1-1 + 0 = 100100 x99 + 9999 x98 + …+ 22 x1 + x0 + 0 = x99 + x98 + …..+ x + 1 + 0 = x99 + x98 + … + x + 1 Hence , f’ (x) = x99 + x98 + … + x + 1 We need to prove f’(1) = 100 f’(0) Hence R.H.S = L.H.S Hence proved
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About the Author
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo