Check sibling questions


Transcript

Ex 12.2, 11 Find the derivative of the following functions: (iv) cosec x Let f (x) = cosec x f(x) = 1/sin⁑π‘₯ Let u = 1 & v = sin x ∴ f(x) = 𝑒/𝑣 So, f’(x) = (𝑒/𝑣)^β€² Using quotient rule f’(x) = (𝑒^β€² 𝑣 βˆ’γ€– 𝑣〗^β€² 𝑒)/𝑣^2 Finding u’ & v’ u = 1 u’ = 0 & v = sin x v’ = cos x Now, f’(x) = (𝑒^β€² 𝑣 βˆ’γ€– 𝑣〗^β€² 𝑒)/𝑣^2 = (0 (sin⁑〖π‘₯) βˆ’γ€– cos〗⁑〖π‘₯ (1)γ€— γ€—)/(〖𝑠𝑖𝑛〗^2 π‘₯) (Derivative of constant function = 0) (Derivative of sin x = cos x) = (0 βˆ’ π‘π‘œπ‘  π‘₯)/(〖𝑠𝑖𝑛〗^2 π‘₯) = (βˆ’ π‘π‘œπ‘  π‘₯)/(〖𝑠𝑖𝑛〗^2 π‘₯) = (βˆ’ π‘π‘œπ‘  π‘₯)/sin⁑π‘₯ . 1/sin⁑π‘₯ = – cot x cosec x = – cosec x cot x Hence f’(x) = – cosec x cot x Using cot x = π‘π‘œπ‘ /sin⁑π‘₯ & 1/sin⁑π‘₯ = cosec x

  1. Chapter 12 Class 11 Limits and Derivatives
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo