# Ex 9.4, 3 (Optional) - Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)

Last updated at April 16, 2019 by Teachoo

Ex 9.4 (Optional)

Ex 9.4, 1 (Optional)
Deleted for CBSE Board 2022 Exams

Ex 9.4, 2 (Optional) Important Deleted for CBSE Board 2022 Exams

Ex 9.4, 3 (Optional) Deleted for CBSE Board 2022 Exams You are here

Ex 9.4, 4 (Optional) Deleted for CBSE Board 2022 Exams

Ex 9.4, 5 (Optional) Important Deleted for CBSE Board 2022 Exams

Ex 9.4, 6 (Optional) Deleted for CBSE Board 2022 Exams

Ex 9.4, 7 (Optional) Important Deleted for CBSE Board 2022 Exams

Ex 9.4, 8 (Optional) Important Deleted for CBSE Board 2022 Exams

Last updated at April 16, 2019 by Teachoo

Ex 9.4, 3 (Optional) In Fig. 9.31, ABCD, DCFE and ABFE are parallelograms. Show that ar (ADE) = ar (BCF). Given, ABCD, ABFE and DCFE are parallelograms. Now, In ∆ ADE and ∆ BCF AD = BC AE = BF DE = CF ∴ ∆ADE ≅ ∆BCF Hence, ar (ADE) = ar (BCF) Hence Proved (Opposite sides of a parallelogram ABCD are equal) (Opposite sides of a parallelogram ABFE are equal) (Opposite sides of a parallelogram DCFE are equal) (SSS Congruency) (Area of congruent triangles is equal)