Check sibling questions

Example 15 - Divide 44(x^4 - 5x^3 - 24x^2) by 11x (x - 8) - Chapter 14

Example 15 - Chapter 14 Class 8 Factorisation - Part 2


Transcript

Example 15 Divide 44 (π‘₯^4 – 5π‘₯^3 – 24π‘₯^2) by 11x (x – 8) We first factorize 44 (π‘₯^4 – 5π‘₯^3 – 24π‘₯^2) = 44 (π‘₯^2 Γ— π‘₯^2 βˆ’ 5π‘₯ Γ— π‘₯^2 βˆ’ 24 Γ— π‘₯^2) Taking π‘₯^2 common, = γ€–44π‘₯γ€—^2 (π‘₯^2 βˆ’ 5π‘₯ βˆ’ 24) By middle term splitting, = 44π‘₯^2 (π‘₯^2+3π‘₯ βˆ’ 8π‘₯ βˆ’ 24) = 44π‘₯^2 [(π‘₯^2+3π‘₯) βˆ’ (8π‘₯+24)] Both have x as common factor Both have 8 as common factor Splitting the middle term We need to find two numbers whose Sum = βˆ’5 Product = βˆ’24 So, we write βˆ’5x = 3x βˆ’ 8x = 44π‘₯^2 [π‘₯(π‘₯+3) βˆ’8(π‘₯+3)] Taking π‘₯+3 common, = 44π‘₯^2 (π‘₯+3) (π‘₯ βˆ’ 8) Dividing (44 (π‘₯^4 βˆ’ 5π‘₯^3 βˆ’ 24π‘₯^2 ))/(11π‘₯ (π‘₯ βˆ’ 8)) = (44 π‘₯^2 (π‘₯ + 3) (π‘₯ βˆ’ 8))/(11π‘₯ (π‘₯ βˆ’ 8)) = 44/11 Γ— π‘₯^2/π‘₯ Γ— (π‘₯ + 3) Γ— ((π‘₯ βˆ’ 8))/((π‘₯ βˆ’ 8)) = 4 Γ— π‘₯ Γ— (π‘₯ + 3) = 4𝒙 (𝒙 + 3)

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.