Example 15 - Divide 44(x^4 - 5x^3 - 24x^2) by 11x (x - 8) - Chapter 14

Example 15 - Chapter 14 Class 8 Factorisation - Part 2


Transcript

Example 15 Divide 44 (𝑥^4 – 5𝑥^3 – 24𝑥^2) by 11x (x – 8) We first factorize 44 (𝑥^4 – 5𝑥^3 – 24𝑥^2) = 44 (𝑥^2 × 𝑥^2 − 5𝑥 × 𝑥^2 − 24 × 𝑥^2) Taking 𝑥^2 common, = 〖44𝑥〗^2 (𝑥^2 − 5𝑥 − 24) By middle term splitting, = 44𝑥^2 (𝑥^2+3𝑥 − 8𝑥 − 24) = 44𝑥^2 [(𝑥^2+3𝑥) − (8𝑥+24)] Both have x as common factor Both have 8 as common factor Splitting the middle term We need to find two numbers whose Sum = −5 Product = −24 So, we write −5x = 3x − 8x = 44𝑥^2 [𝑥(𝑥+3) −8(𝑥+3)] Taking 𝑥+3 common, = 44𝑥^2 (𝑥+3) (𝑥 − 8) Dividing (44 (𝑥^4 − 5𝑥^3 − 24𝑥^2 ))/(11𝑥 (𝑥 − 8)) = (44 𝑥^2 (𝑥 + 3) (𝑥 − 8))/(11𝑥 (𝑥 − 8)) = 44/11 × 𝑥^2/𝑥 × (𝑥 + 3) × ((𝑥 − 8))/((𝑥 − 8)) = 4 × 𝑥 × (𝑥 + 3) = 4𝒙 (𝒙 + 3)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.