# Example 12 - Chapter 14 Class 8 Factorisation

Last updated at Dec. 26, 2018 by Teachoo

Last updated at Dec. 26, 2018 by Teachoo

Example 12 Find the factors of γ"3m" γ^2+ 9m + 6. γ"3m" γ^2+ 9m + 6 Taking 3 common, = 3 (π^2+3π+2) By middle term splitting = 3 (π^2+π+2π+2) Both have m as common factor Both have 2 as common factor = 3 [π(π+1)+2(π+1)] Taking (m + 1) common, = π(π+π)(π+π) Splitting the middle term We need to find two numbers whose Sum = 3 Product = 2 So, we write 3m = m + 2m