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Example 2 - Chapter 12 Class 8 Factorisation
Last updated at July 18, 2026 by Teachoo
Chapter 12 Class 8 Factorisation
Serial order wise
Transcript
Example 2 (Method 1) Factorise 10š„^2 ā 18š„^3 + 14š„^4 10š„^2 = 10 Ć š„^2 = 2 Ć 5 Ć š„^2 = 2 Ć 5 Ć š„ Ć š„ 18š„^3 = 18 Ć š„^3 = 2 Ć 3 Ć 3 Ć š„^3 = 2 Ć 3 Ć 3 Ć š„ Ć š„ Ć š„ 14š„^4 = 14 Ć š„^4 = 2 Ć 7 Ć š„^4 = 2 Ć 7 Ć š„ Ć š„ Ć š„ Ć š„ Now, 10š„^2 = 2 Ć 5 Ć š„ Ć š„ 18š„^3 = 2 Ć 3 Ć 3 Ć š„ Ć š„ Ć š„ 14š„^2 = 2 Ć 7 Ć š„ Ć š„ Ć š„ Ć š„ So, 2, š„, š„ are common factors. 10š„^2 + 18š„^3+14š„^4 = (2 Ć 5 Ć š„ Ć š„) ā (2 Ć 3 Ć 3 Ć š„ Ć š„" Ć " š„) + (2 Ć 7 Ć š„ Ć š„ Ć š„ Ć š„) = 2 Ć š„ Ć š„ (5 ā (3 Ć 3 Ć š„) + (7 Ć š„ Ć š„)) = 2š„^2 (5 ā 9š„ + 7š„^2) = 2š^š (7š^š ā 9š + 5) Example 2 (Method 2) Factorise 10š„^2 ā 18š„^3 + 14š„^410š„^2 ā 18š„^3 + 14š„^4 = (2 Ć 5š„^2) ā (2 Ć 9š„^3) + (2 Ć 7š„^4) Taking 2 common from all the terms = 2 (5š„^2 ā 9š„^3 + 7š„^4) = 2 ( (5 Ć š„^2) ā (9š„ Ć š„^2) + (7š„^2 Ć š„^2) ) Taking š„^2 common from all the terms = 2š„^2 (5 ā 9š„ + 7š„^2) = 2š^š (7š^š ā 9š + 5)
