# Example 11 - Chapter 14 Class 8 Factorisation

Last updated at Dec. 26, 2018 by Teachoo

Last updated at Dec. 26, 2018 by Teachoo

Example 11 Obtain the factors of π§^2 β 4z β 12. π§^2 β 4z β 12 By middle term splitting = π§^2+"2z"β6π§ β 12 = (π§^2+"2z" )β(6π§ + 12) Both have z as common factor Both have 6 as common factor = z (z + 2) β 6 (z + 2) Taking (z + 2) common = (z + 2) (z β 6) Splitting the middle term We need to find two numbers whose Sum = β4 Product = β12 So, we write β4z = 2z β 6z