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  1. Chapter 14 Class 8 Factorisation
  2. Serial order wise

Transcript

Example 14 (Method 1 โ€“ Separating each term) Divide 24(๐‘ฅ^2yz + ใ€–๐‘ฅ๐‘ฆใ€—^2z + ใ€–๐‘ฅ๐‘ฆ๐‘งใ€—^2) by 8xyz using both the methods. 24 (๐‘ฅ^2 ๐‘ฆ๐‘ง+๐‘ฅ๐‘ฆ^2 ๐‘ง+๐‘ฅ๐‘ฆ๐‘ง^2 ) = 24 (๐‘ฅร—๐‘ฅ๐‘ฆ๐‘ง+๐‘ฆร—๐‘ฅ๐‘ฆ๐‘ง+๐‘งร—๐‘ฅ๐‘ฆ๐‘ง) Taking xyz common = 24 ๐‘ฅ๐‘ฆ๐‘ง (๐‘ฅ+๐‘ฆ+๐‘ง) Dividing (24 (๐‘ฅ^2 ๐‘ฆ๐‘ง + ๐‘ฅ๐‘ฆ^2 ๐‘ง + ๐‘ฅ๐‘ฆ๐‘ง^2))/8๐‘ฅ๐‘ฆ๐‘ง = (24 ๐‘ฅ๐‘ฆ๐‘ง (๐‘ฅ + ๐‘ฆ + ๐‘ง))/8๐‘ฅ๐‘ฆ๐‘ง = (24 ๐‘ฅ๐‘ฆ๐‘ง (๐‘ฅ + ๐‘ฆ + ๐‘ง))/8๐‘ฅ๐‘ฆ๐‘ง = 3 (๐’™ + ๐’š + ๐’›) Example 14 (Method 2 โ€“ Canceling term) Divide 24(๐‘ฅ^2yz + ใ€–๐‘ฅ๐‘ฆใ€—^2z + ใ€–๐‘ฅ๐‘ฆ๐‘งใ€—^2) by 8xyz using both the methods. (24 (๐‘ฅ^2 ๐‘ฆ๐‘ง + ๐‘ฅ๐‘ฆ^2 ๐‘ง + ๐‘ฅ๐‘ฆ๐‘ง^2))/8๐‘ฅ๐‘ฆ๐‘ง = 24/8 ร— ((๐‘ฅ^2 ๐‘ฆ๐‘ง + ๐‘ฅ๐‘ฆ^2 ๐‘ง + ๐‘ฅ๐‘ฆ๐‘ง^2))/๐‘ฅ๐‘ฆ๐‘ง = 3 ร— ((๐‘ฅ^2 ๐‘ฆ๐‘ง + ๐‘ฅ๐‘ฆ^2 ๐‘ง + ๐‘ฅ๐‘ฆ๐‘ง^2))/๐‘ฅ๐‘ฆ๐‘ง = 3 ร— ((๐‘ฅ^2 ๐‘ฆ๐‘ง )/๐‘ฅ๐‘ฆ๐‘ง+(๐‘ฅ๐‘ฆ^2 ๐‘ง)/๐‘ฅ๐‘ฆ๐‘ง+(๐‘ฅ๐‘ฆ๐‘ง^2)/๐‘ฅ๐‘ฆ๐‘ง) = 3 ร— (๐‘ฅ + ๐‘ฆ + ๐‘ง) = 3 (๐’™ + ๐’š + ๐’›)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.