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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Example 15 A TV was bought at a price of Rs 21,000. After one year the value of the TV was depreciated by 5% (Depreciation means reduction of value due to use and age of the item). Find the value of the TV after one year. TV was bought for Rs 21000 So, P = Rs 21000 Also, TV depreciated by 5% in one year Depreciated means value is decreased So, we Put a Minus sign in rate Rate = −5% Also, Rate is compounded So we use the formula A = P (1+𝑅/100)^𝑛 Here, P = 21000 R = –5 % N = Number of years = 1 Putting Values in Formula A = 21000 (1+((−5))/100)^1 A = 21000 (1−5/100) A = 21,000 × (1−1/20) A = 21,000 × ((20 − 1)/20) A = 21,000 × 19/20 A = 2100/2 × 19 A = 1050 × 19 A = 19950 Value of the TV after one year = Rs 19,950

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.