# Example 15 - Chapter 8 Class 8 Comparing Quantities

Last updated at Nov. 12, 2018 by Teachoo

Examples

Example 1 (i)

Example 1 (ii)

Example 1 (iii) Important

Example 2

Example 3 Important

Example 4

Example 5

Example 6 Important

Example 7 Important

Example 8

Example 9

Example 10 – GST (Page Number - 124)

Example 10 (Page no. 126) Important

Example 11

Example 12

Example 13 Important

Example 14

Example 15 Important You are here

Last updated at Nov. 12, 2018 by Teachoo

Example 15 A TV was bought at a price of Rs 21,000. After one year the value of the TV was depreciated by 5% (Depreciation means reduction of value due to use and age of the item). Find the value of the TV after one year. TV was bought for Rs 21000 So, P = Rs 21000 Also, TV depreciated by 5% in one year Depreciated means value is decreased So, we Put a Minus sign in rate Rate = −5% Also, Rate is compounded So we use the formula A = P (1+𝑅/100)^𝑛 Here, P = 21000 R = –5 % N = Number of years = 1 Putting Values in Formula A = 21000 (1+((−5))/100)^1 A = 21000 (1−5/100) A = 21,000 × (1−1/20) A = 21,000 × ((20 − 1)/20) A = 21,000 × 19/20 A = 2100/2 × 19 A = 1050 × 19 A = 19950 Value of the TV after one year = Rs 19,950