Example 15 - Chapter 8 Class 8 Comparing Quantities
Last updated at Nov. 12, 2018 by Teachoo
Examples
Example 1 (i)
Example 1 (ii)
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Example 2
Example 3 Important
Example 4
Example 5
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Example 8
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Example 10 – GST (Page Number - 124)
Example 10 (Page no. 126) Important
Example 11
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Example 15 Important You are here
Transcript
Example 15 A TV was bought at a price of Rs 21,000. After one year the value of the TV was depreciated by 5% (Depreciation means reduction of value due to use and age of the item). Find the value of the TV after one year. TV was bought for Rs 21000 So, P = Rs 21000 Also, TV depreciated by 5% in one year Depreciated means value is decreased So, we Put a Minus sign in rate Rate = −5% Also, Rate is compounded So we use the formula A = P (1+𝑅/100)^𝑛 Here, P = 21000 R = –5 % N = Number of years = 1 Putting Values in Formula A = 21000 (1+((−5))/100)^1 A = 21000 (1−5/100) A = 21,000 × (1−1/20) A = 21,000 × ((20 − 1)/20) A = 21,000 × 19/20 A = 2100/2 × 19 A = 1050 × 19 A = 19950 Value of the TV after one year = Rs 19,950
