Question 1 - Examples - Chapter 7 Class 8 Comparing Quantities

Last updated at Dec. 16, 2024 by

Example 2 - The price of a scooter was Rs 34,000 last year. It has

Example 2 - Chapter 8 Class 8 Comparing Quantities - Part 2
Example 2 - Chapter 8 Class 8 Comparing Quantities - Part 3
Example 2 - Chapter 8 Class 8 Comparing Quantities - Part 4

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Question 1 (Method 1) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Percentage increase = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/(𝑂𝑙𝑑 π‘π‘Ÿπ‘–π‘π‘’) Γ— 100 20 = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/34000 Γ— 100 20 = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/340 20 Γ— 340 = Increase in price 6800 = Increase in Price ∴ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 ∴ New price is now Rs 40,800 Question 1 (Method 2) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Increase in price = Percentage increase Γ— Old Price = 20% Γ— 34000 = 20/100 Γ— 3400 = 20 Γ— 340 = 6800 ∴ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 ∴ New price is now Rs 40,800

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo