# Example 2 - Chapter 8 Class 8 Comparing Quantities

Last updated at Nov. 12, 2018 by Teachoo

Last updated at Nov. 12, 2018 by Teachoo

Transcript

Example 2 (Method 1) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Percentage increase = (πΌππππππ π ππ πππππ)/(πππ πππππ) Γ 100 20 = (πΌππππππ π ππ πππππ)/34000 Γ 100 20 = (πΌππππππ π ππ πππππ)/340 20 Γ 340 = Increase in price 6800 = Increase in Price β΄ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 β΄ New price is now Rs 40,800 Example 2 (Method 2) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Increase in price = Percentage increase Γ Old Price = 20% Γ 34000 = 20/100 Γ 3400 = 20 Γ 340 = 6800 β΄ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 β΄ New price is now Rs 40,800

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.