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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Example 2 (Method 1) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Percentage increase = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/(𝑂𝑙𝑑 π‘π‘Ÿπ‘–π‘π‘’) Γ— 100 20 = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/34000 Γ— 100 20 = (πΌπ‘›π‘π‘Ÿπ‘’π‘Žπ‘ π‘’ 𝑖𝑛 π‘π‘Ÿπ‘–π‘π‘’)/340 20 Γ— 340 = Increase in price 6800 = Increase in Price ∴ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 ∴ New price is now Rs 40,800 Example 2 (Method 2) The price of a scooter was Rs 34,000 last year. It has increased by 20% this year. What is the price now? Given, Old Price of scooter = 34000 Percentage increase = 20% Increase in price = Percentage increase Γ— Old Price = 20% Γ— 34000 = 20/100 Γ— 3400 = 20 Γ— 340 = 6800 ∴ Increase in Price = 6800 Now, New price = Old Price + Increase in price = 34000 + 6800 = 40800 ∴ New price is now Rs 40,800

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.