# Example 12 - Chapter 8 Class 8 Comparing Quantities

Last updated at Nov. 12, 2018 by Teachoo

Examples

Example 1 (i)

Example 1 (ii)

Example 1 (iii) Important

Example 2

Example 3 Important

Example 4

Example 5

Example 6 Important

Example 7 Important

Example 8

Example 9

Example 10 – GST (Page Number - 124)

Example 10 (Page no. 126) Important

Example 11

Example 12 You are here

Example 13 Important

Example 14

Example 15 Important

Last updated at Nov. 12, 2018 by Teachoo

Example 12 What amount is to be repaid on a loan of Rs 12000 for 1 1/2 years at 10% per annum compounded half yearly. Given Principal = Rs 12000 Here, rate is compounded half yearly. Rate of interest = R = 10/2 % = 5 % & Time = 1 1/2 years = 3/2 years = 3/2 × 2 half years = 3 Amount = P (1+𝑅/100)^𝑛 = 12000 (1+5/100)^3 = 12000 (1+1/20)^3 = 12000 ((20 + 1)/20)^3 = 12000 (21/20)^3 = 12000 × 21/20 × 21/20 × 21/20 = 12 × 21/2 × 21/2 × 21/2 = 3 × 21 × 21 × 21/2 = (63 × 441)/2 = 27783/2 = 13891.5 ∴ Amount = Rs 13,891.50