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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Example 6 A shopkeeper purchased 200 bulbs for Rs 10 each. However 5 bulbs were fused and had to be thrown away. The remaining were sold at Rs 12 each. Find the gain or loss %. Given, Number of bulbs purchased = 200 Cost Price of 1 bulb = Rs 10 ∴ Total Cost Price (CP) = Number of bulbs purchased × Cost Price of 1 Bulb = 200 × 10 = 2000 ∴ CP = Rs 2000 Given, 5 bulbs were fused and thrown away and the remaining were sold. Number of bulbs Sold = Number of bulbs purchased − Number of fused bulbs = 200 − 5 = 195 Selling Price of one bulb = 12 Total Selling Price (SP) = Number of bulbs sold × Selling Price of 1 bulb = 195 × 12 = 2340 Therefore, CP = Rs 2000 & SP = Rs 2340 Since SP > CP, He made a Profit Profit = SP − CP = 2340 − 2000 = 340 Also, Gain Percentage = 𝐺𝑎𝑖𝑛/𝐶𝑃×100 = 340/2000 × 100 = 34/2 = 17 % ∴ Gain Percentages age = 17 %

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.