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  1. Chapter 8 Class 8 Comparing Quantities
  2. Serial order wise
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Ex 8.1, 1 Find the ratio of the following. (a) Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour.Given, Speed of cycle = 15 km per Hour & Speed of Scooter = 30 km per hour Ratio = (๐‘†๐‘๐‘’๐‘’๐‘‘ ๐‘œ๐‘“ ๐‘๐‘ฆ๐‘๐‘™๐‘’)/(๐‘†๐‘๐‘’๐‘’๐‘‘ ๐‘œ๐‘“ ๐‘ ๐‘๐‘œ๐‘œ๐‘ก๐‘’๐‘Ÿ) = 15/30 = 1/2 = 1 : 2 Ex 8.1, 1 Find the ratio of the following. (b) 5 m to 10 kmRatio = (5 ๐‘š )/(10 ๐‘˜๐‘š) = (5 ๐‘š)/(10 ร— 1000 ๐‘š) = 1/2000 = 1 : 2000 (1 km = 1000 m) Ex 8.1, 1 Find the ratio of the following. (c) 50 paise to Rs 5 Ratio = (50 ๐‘๐‘Ž๐‘–๐‘ ๐‘’)/(5 ๐‘Ÿ๐‘ข๐‘๐‘’๐‘’๐‘ ) = (50 ๐‘๐‘Ž๐‘–๐‘ ๐‘’)/(5 ร— 100 ๐‘ƒ๐‘Ž๐‘–๐‘ ๐‘’) = 1/10 = 1 : 10 (Rs 1 = 100 paise)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.