# Example 11 - Chapter 8 Class 8 Comparing Quantities

Last updated at Nov. 12, 2018 by Teachoo

Examples

Example 1 (i)

Example 1 (ii)

Example 1 (iii) Important

Example 2

Example 3 Important

Example 4

Example 5

Example 6 Important

Example 7 Important

Example 8

Example 9

Example 10 – GST (Page Number - 124)

Example 10 (Page no. 126) Important

Example 11 You are here

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Example 13 Important

Example 14

Example 15 Important

Example 11 Find CI on Rs 12600 for 2 years at 10% per annum compounded annually.Given, Principal (P) = 12600 Time = 2 Years Rate (R) = 10% per annum We use the formula A = P ("1 + " 𝑟/100)^𝑛 where A = Amount after n years A = 12600 ("1 + " 10/100)^2 = 12600 ("1 + " 1/10)^2 = 12600 ((10 + 1)/10)^2 = 12600 (11/10)^2 = 12600 (11/10)^2 = 12600 × 121/100 = 126 × 121 = 15246 ∴ Amount after 2 years = Rs 15,246 Now, Amount = Principal + Interest 15246 = 12600 + Interest 15246 – 12600 = Interest 2646 = Interest Interest = 2646 ∴ Compound Interest = Rs 2,646