Question 29
The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.
CBSE Class 10 Sample Paper for 2019 Boards
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CBSE Class 10 Sample Paper for 2019 Boards
Last updated at Oct. 1, 2019 by Teachoo
Question 29
The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.
Question 29 The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface. Here, the bucket is in the shape of a frustum Where h = height = 16 cm r1 = radius of upper end = 20 cm r2 = radius of lower end = 8 cm We need to find its Curved Surface Area Curved Surface Area of frustum = π(π1+π2)π We need to find l We know that π = β(β2+(π1βπ2)2) π = β(242+(15β5)2) π = β(242+102) π = β(576+100) π = β676 π = β(γ26γ^2 ) π = 26 cm Now, Curved surface area of frustum = π(π1+π2)π = π(15+5)Γ26 = 22/7Γ20Γ26 = (440 Γ 26)/7 = 11440/7 = 1634.28 cm2 β΄ Curved surface area of frustum = 1634.28 cm2