Question 29

The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.   Subscribe to our Youtube Channel - https://you.tube/teachoo

1. Class 10
2. Solutions of Sample Papers for Class 10 Boards
3. CBSE Class 10 Sample Paper for 2019 Boards

Transcript

Question 29 The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface. Here, the bucket is in the shape of a frustum Where h = height = 16 cm r1 = radius of upper end = 20 cm r2 = radius of lower end = 8 cm We need to find its Curved Surface Area Curved Surface Area of frustum = 𝜋(𝑟1+𝑟2)𝑙 We need to find l We know that 𝑙 = √(ℎ2+(𝑟1−𝑟2)2) 𝑙 = √(242+(15−5)2) 𝑙 = √(242+102) 𝑙 = √(576+100) 𝑙 = √676 𝑙 = √(〖26〗^2 ) 𝑙 = 26 cm Now, Curved surface area of frustum = 𝜋(𝑟1+𝑟2)𝑙 = 𝜋(15+5)×26 = 22/7×20×26 = (440 × 26)/7 = 11440/7 = 1634.28 cm2 ∴ Curved surface area of frustum = 1634.28 cm2

CBSE Class 10 Sample Paper for 2019 Boards

Class 10
Solutions of Sample Papers for Class 10 Boards 