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Question 29
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The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.

Last updated at Oct. 1, 2019 by Teachoo

**
Question 29
**

The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface.

Transcript

Question 29 The radii of circular ends of a bucket of height 24 cm are 15 cm and 5 cm. Find the area of its curved surface. Here, the bucket is in the shape of a frustum Where h = height = 16 cm r1 = radius of upper end = 20 cm r2 = radius of lower end = 8 cm We need to find its Curved Surface Area Curved Surface Area of frustum = ๐(๐1+๐2)๐ We need to find l We know that ๐ = โ(โ2+(๐1โ๐2)2) ๐ = โ(242+(15โ5)2) ๐ = โ(242+102) ๐ = โ(576+100) ๐ = โ676 ๐ = โ(ใ26ใ^2 ) ๐ = 26 cm Now, Curved surface area of frustum = ๐(๐1+๐2)๐ = ๐(15+5)ร26 = 22/7ร20ร26 = (440 ร 26)/7 = 11440/7 = 1634.28 cm2 โด Curved surface area of frustum = 1634.28 cm2

CBSE Class 10 Sample Paper for 2019 Boards

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Class 10

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.