Question 26 - Draw a ABC with sides 6 cm, 8 cm, 9 cm and construct

Question 26 Draw a ∆ABC with sides 6 cm, 8 cm and 9 cm and then construct a triangle similar to ∆ABC whose sides are 3/5 of the corresponding sides of ∆ABC. Let’s first construct Δ ABC with sides 6 cm, 8 cm, 9 cm Steps to draw Δ ABC Draw base AB of side 6 cm With A as center, and 8 cm as radius, draw an arc With B as center, and 9 cm as radius, draw an arc 3. Let C be the point where the two arcs intersect. Join AC & BC Thus, Δ ABC is the required triangle Now, let’s make a similar triangle with Scale factor = 3/5 Steps of construction Draw any ray AX making an acute angle with AB on the side opposite to the vertex C. Mark 5 (the greater of 3 and 5 in 3/5 ) points 𝐴_1, 𝐴_2, 𝐴_3, 𝐴_4, 𝐴_5 on AX so that 〖𝐴𝐴〗_1=𝐴_1 𝐴_2=𝐴_2 𝐴_3=𝐴_3 𝐴_4=𝐴_4 𝐴_5 Join 𝐴_5B and draw a line through 𝐴_3 (the 3rd point, 3 being smaller of 3 and 5 in 3/5) parallel to 𝐴_5 𝐵, to intersect AB at B′. 4. Draw a line through B′ parallel to the line BC to intersect AC at C′. Thus, Δ AB’C′ is the required triangle

Question 26 - CBSE Class 10 Sample Paper for 2019 Boards