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CBSE Class 10 Sample Paper for 2019 Boards

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Question 9 - CBSE Class 10 Sample Paper for 2019 Boards - Solutions of Sample Papers for Class 10 Boards

Last updated at March 23, 2023 by

Question 9

Find the coordinates of the point P which divides the join of A (–2, 5) and B(3, –5) in the ratio 2 : 3

Find coordinates of point P which divides the join of A (-2, 5) and B

Question 9 - CBSE Class 10 Sample Paper for 2019 Boards - Part 2
Question 9 - CBSE Class 10 Sample Paper for 2019 Boards - Part 3

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Transcript

Question 9 Find the coordinates of the point P which divides the join of A (–2, 5) and B(3, –5) in the ratio 2 : 3 Let coordinates of point P be P (x, y) Given that P divides AB in the ratio 2 : 3 Now, the formula is x = (π‘š_1 π‘₯_2 + π‘š_2 π‘₯_1)/(π‘š_1 + π‘š_2 ) y = (π‘š_1 𝑦_2 + π‘š_2 𝑦_1)/(π‘š_1 + π‘š_2 ) Here, m1 = 2 , m2 = 3 x1 = βˆ’2 , x2 = 3 y1 = 5, y2 = –5 x-coordinate x = (π‘š_1 π‘₯_2 + π‘š_2 π‘₯_1)/(π‘š_1 + π‘š_2 ) x = (2 Γ— 3 + 3 Γ— (βˆ’2))/(2 + 3) x = (6 βˆ’ 6)/5 x = 0/5 x = 0 y-coordinate y = (π‘š_1 𝑦_2 + π‘š_2 𝑦_1)/(π‘š_1 + π‘š_2 ) y = (2 Γ— (βˆ’5) + 3 Γ— 5)/(2 + 3) y = (βˆ’10 + 15)/5 y = 5/5 y = 1 So, coordinates of point point P = (x, y) = (0, 1)

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