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Question 9
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Find the coordinates of the point P which divides the join of A (–2, 5) and B(3, –5) in the ratio 2 : 3

Last updated at Nov. 22, 2018 by Teachoo

**
Question 9
**

Find the coordinates of the point P which divides the join of A (–2, 5) and B(3, –5) in the ratio 2 : 3

Transcript

Question 9 Find the coordinates of the point P which divides the join of A (โ2, 5) and B(3, โ5) in the ratio 2 : 3 Let coordinates of point P be P (x, y) Given that P divides AB in the ratio 2 : 3 Now, the formula is x = (๐_1 ๐ฅ_2 + ๐_2 ๐ฅ_1)/(๐_1 + ๐_2 ) y = (๐_1 ๐ฆ_2 + ๐_2 ๐ฆ_1)/(๐_1 + ๐_2 ) Here, m1 = 2 , m2 = 3 x1 = โ2 , x2 = 3 y1 = 5, y2 = โ5 x-coordinate x = (๐_1 ๐ฅ_2 + ๐_2 ๐ฅ_1)/(๐_1 + ๐_2 ) x = (2 ร 3 + 3 ร (โ2))/(2 + 3) x = (6 โ 6)/5 x = 0/5 x = 0 y-coordinate y = (๐_1 ๐ฆ_2 + ๐_2 ๐ฆ_1)/(๐_1 + ๐_2 ) y = (2 ร (โ5) + 3 ร 5)/(2 + 3) y = (โ10 + 15)/5 y = 5/5 y = 1 So, coordinates of point point P = (x, y) = (0, 1)

CBSE Class 10 Sample Paper for 2019 Boards

Paper Summary

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Question 9 You are here

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Class 10

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.