Question 9
Find the coordinates of the point P which divides the join of A (β2, 5) and B(3, β5) in the ratio 2 : 3
Last updated at Oct. 1, 2019 by
Question 9
Find the coordinates of the point P which divides the join of A (β2, 5) and B(3, β5) in the ratio 2 : 3
Transcript
Question 9 Find the coordinates of the point P which divides the join of A (β2, 5) and B(3, β5) in the ratio 2 : 3 Let coordinates of point P be P (x, y) Given that P divides AB in the ratio 2 : 3 Now, the formula is x = (π_1 π₯_2 + π_2 π₯_1)/(π_1 + π_2 ) y = (π_1 π¦_2 + π_2 π¦_1)/(π_1 + π_2 ) Here, m1 = 2 , m2 = 3 x1 = β2 , x2 = 3 y1 = 5, y2 = β5 x-coordinate x = (π_1 π₯_2 + π_2 π₯_1)/(π_1 + π_2 ) x = (2 Γ 3 + 3 Γ (β2))/(2 + 3) x = (6 β 6)/5 x = 0/5 x = 0 y-coordinate y = (π_1 π¦_2 + π_2 π¦_1)/(π_1 + π_2 ) y = (2 Γ (β5) + 3 Γ 5)/(2 + 3) y = (β10 + 15)/5 y = 5/5 y = 1 So, coordinates of point point P = (x, y) = (0, 1)
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CBSE Class 10 Sample Paper for 2019 Boards
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