Question 9

Find the coordinates of the point P which divides the join of A (–2, 5) and B(3, –5) in the ratio 2 : 3

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Question 9 Find the coordinates of the point P which divides the join of A (โ€“2, 5) and B(3, โ€“5) in the ratio 2 : 3 Let coordinates of point P be P (x, y) Given that P divides AB in the ratio 2 : 3 Now, the formula is x = (๐‘š_1 ๐‘ฅ_2 + ๐‘š_2 ๐‘ฅ_1)/(๐‘š_1 + ๐‘š_2 ) y = (๐‘š_1 ๐‘ฆ_2 + ๐‘š_2 ๐‘ฆ_1)/(๐‘š_1 + ๐‘š_2 ) Here, m1 = 2 , m2 = 3 x1 = โˆ’2 , x2 = 3 y1 = 5, y2 = โ€“5 x-coordinate x = (๐‘š_1 ๐‘ฅ_2 + ๐‘š_2 ๐‘ฅ_1)/(๐‘š_1 + ๐‘š_2 ) x = (2 ร— 3 + 3 ร— (โˆ’2))/(2 + 3) x = (6 โˆ’ 6)/5 x = 0/5 x = 1 y-coordinate y = (๐‘š_1 ๐‘ฆ_2 + ๐‘š_2 ๐‘ฆ_1)/(๐‘š_1 + ๐‘š_2 ) y = (2 ร— (โˆ’5) + 3 ร— 5)/(2 + 3) y = (โˆ’10 + 15)/5 y = 5/5 y = 1 So, coordinates of point point P = (x, y) = (0, 1)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.