Question 3 (OR 1 ^{ st } question)
Write the value of cot ^{ 2 } θ - 1/sin ^{ 2 } θ
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Last updated at Oct. 1, 2019 by Teachoo
Question 3 (OR 1 ^{ st } question)
Write the value of cot ^{ 2 } θ - 1/sin ^{ 2 } θ
Transcript
Question 3 (OR 1st question) Write the value of cot^2𝜃−1/sin^2𝜃 cot^2𝜃−1/sin^2𝜃 Writing cot θ = cos𝜃/sin𝜃 = (cos𝜃/sin𝜃 )^2−1/sin^2𝜃 = cos^2𝜃/sin^2𝜃 −1/sin^2𝜃 = (cos^2𝜃 − 1)/sin^2𝜃 Now, sin2 θ + cos2 θ = 1 cos2 θ = 1 – sin2 θ = ((1 − sin^2𝜃) − 1)/sin^2𝜃 = (− sin^2𝜃)/sin^2𝜃 = –1
CBSE Class 10 Sample Paper for 2019 Boards
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CBSE Class 10 Sample Paper for 2019 Boards
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