Question 3 (OR 1 st question)

Write the value of cot 2 ⁑θ - 1/sin 2 ⁑θ

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Question 3 (OR 1st question) Write the value of cot^2β‘πœƒβˆ’1/sin^2β‘πœƒ cot^2β‘πœƒβˆ’1/sin^2β‘πœƒ Writing cot ΞΈ = cosβ‘πœƒ/sinβ‘πœƒ = (cosβ‘πœƒ/sinβ‘πœƒ )^2βˆ’1/sin^2β‘πœƒ = cos^2β‘πœƒ/sin^2β‘πœƒ βˆ’1/sin^2β‘πœƒ = (cos^2β‘πœƒ βˆ’ 1)/sin^2β‘πœƒ Now, sin2 ΞΈ + cos2 ΞΈ = 1 cos2 ΞΈ = 1 – sin2 ΞΈ = ((1 βˆ’ sin^2β‘πœƒ) βˆ’ 1)/sin^2β‘πœƒ = (βˆ’ sin^2β‘πœƒ)/sin^2β‘πœƒ = –1

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.