Question 8 - CBSE Class 12 Sample Paper for 2018 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at December 16, 2024 by

Find the approximate change in the value of 1/x 2 , when x changes from x = 2 to x = 2.002

This is a question of CBSE Sample Paper - Class 12 - 2017/18.

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Find approximate change in value of 1/x^2, when x changes from 2 to

Question 8 - CBSE Class 12 Sample Paper for 2018 Boards - Part 2

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Transcript

Question 8 Find the approximate change in the value of 1/π‘₯^2 , when x changes from x = 2 to x = 2.002 Let y = 1/π‘₯^2 We need to find change in value of y when x changes from 2 to 0.002 ∴ βˆ†x = 2.002 – 2 = 0.002 We need to find βˆ†y Now, βˆ†y = 𝑑𝑦/𝑑π‘₯ βˆ†x βˆ†y = 𝑑(1/π‘₯^2 )/𝑑π‘₯ βˆ†x βˆ†y = 𝑑(π‘₯^(βˆ’2) )/𝑑π‘₯ Γ— 0.002 βˆ†y = –2 Γ— x–3 Γ— 0.002 Since we go from x = 2 to x = 2.002 We put x = 2 in βˆ†y βˆ†y = –2 Γ— 2–3 Γ— 0.002 βˆ†y = –2 Γ— 1/2^3 Γ— 0.002 βˆ†y = –2 Γ— 1/2^3 Γ— 2/1000 βˆ†y = (βˆ’1)/2000 βˆ†y = – 0.0005 ∴ y decreases by 0.0005

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo