Find the Projection (vector) of 2i − j + k on i − 2j + k

This is a question of CBSE Sample Paper - Class 12 - 2017/18.

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Find Projection (vector) of 2i - j + k on i - 2j + k - Teachoo

Question 11 - CBSE Class 12 Sample Paper for 2018 Boards - Part 2
Question 11 - CBSE Class 12 Sample Paper for 2018 Boards - Part 3

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Question 11 Find the Projection (vector) of 2š‘– Ģ‚ āˆ’ š‘— Ģ‚ + š‘˜ Ģ‚ on š‘– Ģ‚ āˆ’ 2š‘— Ģ‚ + š‘˜ Ģ‚ Let a = 2š‘– Ģ‚ āˆ’ š‘— Ģ‚ + š‘˜ Ģ‚ and b = š‘– Ģ‚ āˆ’ 2š‘— Ģ‚ + š‘˜ Ģ‚ We need to find Projection (vector) of š‘Ž āƒ— on š‘ āƒ— Theory We know that Projection of š‘Ž āƒ— on š‘ āƒ— = 1/("|" š‘ āƒ—"|" ) (š‘Ž āƒ—. š‘ āƒ—) But here, we are asked projection (vector) So, we multiply projection by š‘ āƒ—/|š‘ āƒ— | Projection (vector) of š‘Ž āƒ— on š‘ āƒ— = 1/|š‘ āƒ— | (š‘Ž āƒ—. š‘ āƒ—) Ɨ š‘ āƒ—/|š‘ āƒ— | = ((š‘Ž āƒ— . š‘ āƒ— ))/|š‘ āƒ— |^2 Ɨ š‘ āƒ— (š’‚ āƒ—. š’ƒ āƒ—) = (2 Ɨ 1) + (–1 Ɨ –2) + (1 Ɨ 1) = 2 + 2 + 1 = 5 Magnitude of š‘ āƒ— = √(12+(āˆ’2)2+12) |š‘ āƒ— | = √(1+4+1) = √6 Projection (vector) of š’‚ āƒ— on š’ƒ āƒ— = ((š‘Ž āƒ— . š‘ āƒ— ))/|š‘ āƒ— |^2 Ɨ š‘ āƒ— = 5/(√6)^2 Ɨ ( š‘– Ģ‚ āˆ’ 2š‘— Ģ‚ + š‘˜ Ģ‚) = šŸ“/šŸ” ( š’Š Ģ‚ āˆ’ 2š’‹ Ģ‚ + š’Œ Ģ‚)

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