If 4sin −1 x + cos −1 x = ๐œ‹ then find the value of x.

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Question 5 If 4sinโˆ’1 x + cosโˆ’1 x = ๐œ‹ then find the value of x. 4sinโˆ’1 x + cosโˆ’1 x = ๐œ‹ We know that sinโˆ’1 x + cosโˆ’1 x = ๐œ‹/2 cosโˆ’1 x = ๐œ‹/2โˆ’"sinโˆ’1 x" 4sinโˆ’1 x + ๐…/๐Ÿโˆ’"sinโˆ’1 x" = ๐œ‹ 4sinโˆ’1 x โˆ’ "sinโˆ’1 x" = ๐œ‹ โ€“ ๐œ‹/2 3sinโˆ’1 x = ๐œ‹/2 sinโˆ’1 x = 1/3 ร— ๐œ‹/2 sinโˆ’1 x = ๐œ‹/6 sinโˆ’1 x = ๐œ‹/6 x = sin ๐œ‹/6 x = sin (180ยฐ)/6 x = sin 30ยฐ x = ๐Ÿ/๐Ÿ

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